Question

在Scala中，您可以使用模式匹配来生成结果，具体取决于输入的类型。例如：

val title = content match {
    case blogPost: BlogPost => blogPost.blog.title + ": " + blogPost.title
    case blog: Blog => blog.title
}

在C＃中，我最好能够写下来：

var title = Visit(content,
    (BlogPost blogPost) => blogPost.Blog.Title + ": " + blogPost.Title,
    (Blog blog) => blog.Title
);

这可能吗？当我尝试将其作为单一方法编写时，我不知道如何指定泛型。除了让类型检查器允许接受T：

的子类型的函数之外，以下实现似乎是正确的

    public TResult Visit<T, TResult>(T value, params Func<T, TResult>[] visitors)
    {
        foreach (var visitor in visitors)
        {
            if (visitor.Method.GetGenericArguments()[0].IsAssignableFrom(value.GetType()))
            {
                return visitor(value);
            }
        }
        throw new ApplicationException("No match");
    }

我最接近的是将函数单独添加到对象，然后调用值访问：

    public class Visitor<T, TResult>
    {
        private class Result
        {
            public bool HasResult;
            public TResult ResultValue;
        }

        private readonly IList<Func<T, Result>> m_Visitors = new List<Func<T, Result>>();

        public TResult Visit(T value)
        {
            foreach (var visitor in m_Visitors)
            {
                var result = visitor(value);
                if (result.HasResult)
                {
                    return result.ResultValue;
                }
            }
            throw new ApplicationException("No match");
        }

        public Visitor<T, TResult> Add<TIn>(Func<TIn, TResult> visitor) where TIn : T
        {
            m_Visitors.Add(value =>
            {
                if (value is TIn)
                {
                    return new Result { HasResult = true, ResultValue = visitor((TIn)value) };
                }
                return new Result { HasResult = false };
            });
            return this;
        }
    }

这可以这样使用：

var title = new Visitor<IContent, string>()
    .Add((BlogPost blogPost) => blogPost.Blog.Title + ": " + blogPost.Title)
    .Add((Blog blog) => blog.Title)
    .Visit(content);

知道如何使用单个方法调用来完成此操作吗？

Answer 1

模式匹配是F＃等函数式编程语言中最常见的功能之一。在codeplex中有一个名为Functional C#的伟大项目。请考虑以下F＃代码：

let operator x = match x with
                 | ExpressionType.Add -> "+"

let rec toString exp = match exp with
                       | LambdaExpression(args, body) -> toString(body)
                       | ParameterExpression(name) -> name
                       | BinaryExpression(op,l,r) -> sprintf "%s %s %s" (toString l) (operator op) (toString r)

使用Functional C＃库，C＃等价物将是：

var Op = new Dictionary<ExpressionType, string> { { ExpressionType.Add, "+" } };

Expression<Func<int,int,int>> add = (x,y) => x + y;

Func<Expression, string> toString = null;
 toString = exp =>
 exp.Match()
    .With<LambdaExpression>(l => toString(l.Body))
    .With<ParameterExpression>(p => p.Name)
    .With<BinaryExpression>(b => String.Format("{0} {1} {2}", toString(b.Left), Op[b.NodeType], toString(b.Right)))
    .Return<string>();

Answer 2

使用Functional C＃（来自@Alireza）

var title = content.Match()
   .With<BlogPost>(blogPost => blogPost.Blog.Title + ": " + blogPost.Title)
   .With<Blog>(blog => blog.Title)
   .Result<string>();

Answer 3

为了确保完全模式匹配，您需要将该函数构建到类型本身中。我就是这样做的：

public abstract class Content
{
    private Content() { }

    public abstract T Match<T>(Func<Blog, T> convertBlog, Func<BlogPost, T> convertPost);

    public class Blog : Content
    {
        public Blog(string title)
        {
            Title = title;
        }
        public string Title { get; private set; }

        public override T Match<T>(Func<Blog, T> convertBlog, Func<BlogPost, T> convertPost)
        {
            return convertBlog(this);
        }
    }

    public class BlogPost : Content
    {
        public BlogPost(string title, Blog blog)
        {
            Title = title;
            Blog = blog;
        }
        public string Title { get; private set; }
        public Blog Blog { get; private set; }

        public override T Match<T>(Func<Blog, T> convertBlog, Func<BlogPost, T> convertPost)
        {
            return convertPost(this);
        }
    }

}

public static class Example
{
    public static string GetTitle(Content content)
    {
        return content.Match(blog => blog.Title, post => post.Blog.Title + ": " + post.Title);
    }
}

Answer 4

查看我的模式匹配实现：repo

它基于表达式，因此它提供了与嵌套ifs相同的性能。

使用示例：

string s1 = "Hello";
string s2 = null;

Func<Option<string>> match = new Matcher<Option<string>>
{
     {s => s is None, s => Console.WriteLine("None")},
     {s => s is Some, s => Console.WriteLine((string)s) // or s.Value
};

match(s1); // Hello
match(s2); // None

通过NuGet提供：Nuget package

Answer 5

我正在使用的通用实现，可以匹配类型，条件或值：

export class YourComponent {
   constructor(private _ngZone: NgZone) {}

在您的情况下，使用情况如下：

public static class Match
{
    public static PatternMatch<T, R> With<T, R>(T value)
    {
        return new PatternMatch<T, R>(value);
    }

    public struct PatternMatch<T, R>
    {
        private readonly T _value;
        private R _result;

        private bool _matched;

        public PatternMatch(T value)
        {
            _value = value;
            _matched = false;
            _result = default(R);
        }

        public PatternMatch<T, R> When(Func<T, bool> condition, Func<R> action)
        {
            if (!_matched && condition(_value))
            {
                _result = action();
                _matched = true;
            }

            return this;
        }

        public PatternMatch<T, R> When<C>(Func<C, R> action)
        {
            if (!_matched && _value is C)
            {
                _result = action((C)(object)_value);
                _matched = true;
            }
            return this;
        }


        public PatternMatch<T, R> When<C>(C value, Func<R> action)
        {
            if (!_matched && value.Equals(_value))
            {
                _result = action();
                _matched = true;
            }
            return this;
        }


        public R Result => _result;

        public R Default(Func<R> action)
        {
            return !_matched ? action() : _result;
        }
    }
}

其他一些例子：

Match.With<IContent, string>(content)
     .When<BlogPost>(blogPost => blogPost.Blog.Title)
     .When<Blog>(blog => blog.Title)
     .Result; // or just .Default(()=> "none");

在C＃中实现模式匹配

5 个答案: