使用swiftUI进行生物特征认证评估

时间:2020-02-19 10:01:24

标签: swift swiftui localauthentication

我已经能够在我的应用程序中使用基本的Face / Touch ID版本。但是,我想添加更好的后备和错误处理。

所以我一直在研究如何做到这一点。像这样的奇妙资源:

Face ID evaluation process not working properly

但是,我找不到任何可在SwiftUI视图中使用的东西。目前,我的项目无法运行:

'unowned' may only be applied to class and class-bound protocol types, not 'AuthenticateView'

Value of type 'AuthenticateView' has no member 'present'

任何帮助将不胜感激。谢谢!

这是AuthenticateView.swift中的代码

func Authenticate(completion: @escaping ((Bool) -> ())){

    //Create a context
    let authenticationContext = LAContext()
    var error:NSError?

    //Check if device have Biometric sensor
    let isValidSensor : Bool = authenticationContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error)

    if isValidSensor {
        //Device have BiometricSensor
        //It Supports TouchID

        authenticationContext.evaluatePolicy(
            .deviceOwnerAuthenticationWithBiometrics,
            localizedReason: "Touch / Face ID authentication",
            reply: { [unowned self] (success, error) -> Void in

                if(success) {
                    // Touch / Face ID recognized success here
                    completion(true)
                } else {
                    //If not recognized then
                    if let error = error {
                        let strMessage = self.errorMessage(errorCode: error._code)
                        if strMessage != ""{
                            self.showAlertWithTitle(title: "Error", message: strMessage)
                        }
                    }
                    completion(false)
                }
        })
    } else {

        let strMessage = self.errorMessage(errorCode: (error?._code)!)
        if strMessage != ""{
            self.showAlertWithTitle(title: "Error", message: strMessage)
        }
    }
}
func errorMessage(errorCode:Int) -> String{

    var strMessage = ""

    switch errorCode {

    case LAError.Code.authenticationFailed.rawValue:
        strMessage = "Authentication Failed"

    case LAError.Code.userCancel.rawValue:
        strMessage = "User Cancel"

    case LAError.Code.systemCancel.rawValue:
        strMessage = "System Cancel"

    case LAError.Code.passcodeNotSet.rawValue:
        strMessage = "Please goto the Settings & Turn On Passcode"

    case LAError.Code.touchIDNotAvailable.rawValue:
        strMessage = "TouchI or FaceID DNot Available"

    case LAError.Code.touchIDNotEnrolled.rawValue:
        strMessage = "TouchID or FaceID Not Enrolled"

    case LAError.Code.touchIDLockout.rawValue:
        strMessage = "TouchID or FaceID Lockout Please goto the Settings & Turn On Passcode"

    case LAError.Code.appCancel.rawValue:
        strMessage = "App Cancel"

    case LAError.Code.invalidContext.rawValue:
        strMessage = "Invalid Context"

    default:
        strMessage = ""

    }
    return strMessage
}
func showAlertWithTitle( title:String, message:String ) {
    let alert = UIAlertController(title: title, message: message, preferredStyle: .alert)

    let actionOk = UIAlertAction(title: "OK", style: .default, handler: nil)
    alert.addAction(actionOk)
    self.present(alert, animated: true, completion: nil)
}

1 个答案:

答案 0 :(得分:1)

说明:

“未拥有”仅可应用于类和类绑定的协议类型,不适用于“ AuthenticateView”

首先,您拥有AuthenticateView,即structclass无法做到这一点,因为整个Apple的SwiftUI理念is about structures.而且因为Struct是值类型而不是引用类型,因此也没有这样的指针。因此,您不得将包含unowned selfweak self修饰符的代码部分包含在struct AuthenticateView: View {}

'AuthenticateView'类型的值没有成员'present'

presentUIViewController的方法。在SwiftUI中,您无权访问。警报将使用下一种样式呈现:

struct ContentView: View {
    @State private var show = false
    var body: some View {
        Button(action: { self.show = true }) { Text("Click") }
        .alert(isPresented: $showingAlert) {
            Alert(title: Text("Title"), 
                message: Text("Message"), 
          dismissButton: .default(Text("Close")))
        }
    }
}

解决方案: 对于您的情况,我将为您的逻辑创建一个class的{​​{1}}处理程序子类,并使用ObservableObject@ObservedObject@Published的功能。

理解概念的粗略示例:

@State
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