Question

在下面的示例中，我有两个数据集（Z和A）。我想通过ILMN号码合并或组合这些集合。如果没有匹配，请填写NA。

z <- matrix(c(0,0,1,1,0,0,1,1,0,0,0,0,1,0,1,1,0,1,1,1,1,0,0,0,"RND1","WDR", "PLAC8","TYBSA","GRA","TAF"), nrow=6,
    dimnames=list(c("ILMN_1651838","ILMN_1652371","ILMN_1652464","ILMN_1652952","ILMN_1653026","ILMN_1653103"),c("A","B","C","D","symbol")))

t<-matrix(c("GO:0002009", 8, 342, 1, 0.07, 0.679, 0, 0, 1, 0, 
        "GO:0030334", 6, 343, 1, 0.07, 0.065, 0, 0, 1, 0,
        "GO:0015674", 7, 350, 1, 0.07, 0.065, 1, 0, 0, 0), nrow=10, dimnames= list(c("GO.ID","LEVEL","Annotated","Significant","Expected","resultFisher","ILMN_1652464","ILMN_1651838","ILMN_1711311","ILMN_1653026")))

结果如下：

             [,1]         [,2]         [,3]         [,4]
GO.ID        "GO:0002009" "GO:0030334" "GO:0015674"  NA
LEVEL        "8"          "6"          "7"           NA
Annotated    "342"        "343"        "350"         NA
Significant  "1"          "1"          "1"           NA
Expected     "0.07"       "0.07"       "0.07"        NA
resultFisher "0.679"      "0.065"      "0.065"       NA
ILMN_1652464 "0"          "0"          "1"           PLAC8
ILMN_1651838 "0"          "0"          "0"           RND1
ILMN_1711311 "1"          "1"          "0"           NA
ILMN_1653026 "0"          "0"          "0"           GRA

Answer 1

使用合并并将t向量重命名为tt（参见Andrie的PS）：

merge(tt,z,by="row.names",all.x=TRUE)[,-(5:8)]

现在，如果你使用数据帧而不是矩阵，这甚至可以变得更容易：

z <- as.data.frame(z)
tt <- as.data.frame(tt)
merge(tt,z["symbol"],by="row.names",all.x=TRUE)

Answer 2

使用match返回所需的向量，然后cbind将其添加到矩阵

cbind(t, z[, "symbol"][match(rownames(t), rownames(z))])

             [,1]         [,2]         [,3]         [,4]   
GO.ID        "GO:0002009" "GO:0030334" "GO:0015674" NA     
LEVEL        "8"          "6"          "7"          NA     
Annotated    "342"        "343"        "350"        NA     
Significant  "1"          "1"          "1"          NA     
Expected     "0.07"       "0.07"       "0.07"       NA     
resultFisher "0.679"      "0.065"      "0.065"      NA     
ILMN_1652464 "0"          "0"          "1"          "PLAC8"
ILMN_1651838 "0"          "0"          "0"          "RND1" 
ILMN_1711311 "1"          "1"          "0"          NA     
ILMN_1653026 "0"          "0"          "0"          "GRA"

PS。警告 t是用于转置矩阵的基本R函数。通过创建一个名为t的变量，可能会导致下游代码混淆。

Answer 3

不完美但很接近：

newcol<-sapply(rownames(t), function(rn){z[match(rn, rownames(z)), 5]})
cbind(data.frame(t), newcol)

Answer 4

cbind.fill <- function(x, y){
  xrn <- rownames(x)
  yrn <- rownames(y)
  rn <- union(xrn, yrn)
  xcn <- colnames(x)
  ycn <- colnames(y)
  if(is.null(xrn) | is.null(yrn) | is.null(xcn) | is.null(ycn)) 
    stop("NULL rownames or colnames")
  z <- matrix(NA, nrow=length(rn), ncol=length(xcn)+length(ycn))
  rownames(z) <- rn
  colnames(z) <- c(xcn, ycn)
  idx <- match(rn, xrn)
  z[!is.na(idx), 1:length(xcn)] <- x[na.omit(idx),]
  idy <- match(rn, yrn)
  z[!is.na(idy), length(xcn)+(1:length(ycn))] <- y[na.omit(idy),]
  return(z)
}

Answer 5

你可以将-Andrie答案包装成通用函数

mbind<-function(...){
 Reduce( function(x,y){cbind(x,y[match(row.names(x),row.names(y)),])}, list(...) )
}

在这里，您可以使用rownames作为键

绑定多个帧

通过rownames合并或组合

5 个答案: