Question

我正在编写一个Android应用程序的代码，该应用程序应该获取数据，将其打包为Json并将其发布到Web服务器，而后者应该使用json进行响应。

使用GET请求工作正常，但由于某些原因使用POST，所有数据似乎都被剥离，服务器也没有收到任何内容。

以下是代码片段：

HttpParams params = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(params, 5000);
HttpConnectionParams.setSoTimeout(params, 5000);        
DefaultHttpClient httpClient = new DefaultHttpClient(params);
BasicCookieStore cookieStore = new BasicCookieStore();
httpClient.setCookieStore(cookieStore);

String uri = JSON_ADDRESS;
String result = "";
String username = "user";
String apikey = "something";
String contentType = "application/json";

JSONObject jsonObj = new JSONObject();

try {
    jsonObj.put("username", username);
    jsonObj.put("apikey", apikey);
} catch (JSONException e) {
    Log.e(TAG, "JSONException: " + e);
}

HttpPost httpPost = new HttpPost(uri);
List<NameValuePair> postParams = new ArrayList<NameValuePair>();
postParams.add(new BasicNameValuePair("json", jsonObj.toString()));
HttpGet httpGet = null;
try {
    UrlEncodedFormEntity entity = new UrlEncodedFormEntity(postParams);
    entity.setContentEncoding(HTTP.UTF_8);
    entity.setContentType("application/json");
    httpPost.setEntity(entity);

    httpPost.setHeader("Content-Type", contentType);
    httpPost.setHeader("Accept", contentType);
} catch (UnsupportedEncodingException e) {
    Log.e(TAG, "UnsupportedEncodingException: " + e);
}

try {
    HttpResponse httpResponse = httpClient.execute(httpPost);
    HttpEntity httpEntity = httpResponse.getEntity();

    if (httpEntity != null) {
        InputStream is = httpEntity.getContent();
        result = StringUtils.convertStreamToString(is);
        Log.i(TAG, "Result: " + result);
    }
} catch (ClientProtocolException e) {
    Log.e(TAG, "ClientProtocolException: " + e);
} catch (IOException e) {
    Log.e(TAG, "IOException: " + e);
}

return result;

我想我已经遵循了关于如何创建参数并发布它们的一般指导原则，但显然没有。

我现在非常欢迎任何有关我找到解决方案的帮助或指示（在花了几个小时意识到没有发送任何帖子数据之后）。真正的服务器在Tomcat上运行Wicket，但我也在一个简单的PHP页面上测试了它，没有区别。

Answer 1

您实际上可以通过以下方式将其作为JSON发送：

// Build the JSON object to pass parameters
JSONObject jsonObj = new JSONObject();
jsonObj.put("username", username);
jsonObj.put("apikey", apikey);
// Create the POST object and add the parameters
HttpPost httpPost = new HttpPost(url);
StringEntity entity = new StringEntity(jsonObj.toString(), HTTP.UTF_8);
entity.setContentType("application/json");
httpPost.setEntity(entity);
HttpClient client = new DefaultHttpClient();
HttpResponse response = client.execute(httpPost);

Answer 2

您是否尝试过没有JSON对象并且只传递了两个basicnamevaluepairs？此外，它可能与您的服务器设置有关

更新：这是我使用的一段代码：

InputStream is = null;
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair("lastupdate", lastupdate)); 

try {
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(connection);
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();
        Log.d("HTTP", "HTTP: OK");
    } catch (Exception e) {
        Log.e("HTTP", "Error in http connection " + e.toString());
    }

Answer 3

我刚刚检查过，我和你有相同的代码，它的工作原理很顺利。唯一的区别是我如何填写我的列表中的参数：

我使用的是：ArrayList<BasicNameValuePair> params

以这种方式填写：

 params.add(new BasicNameValuePair("apikey", apikey);

我不使用任何JSONObject将params发送到webservices。

您是否有义务使用JSONObject？

Answer 4

公共类GetUsers扩展了AsyncTask {

    @Override
    protected void onPreExecute() {
        super.onPreExecute();

    }

    private String convertStreamToString(InputStream is) {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is));
        StringBuilder sb = new StringBuilder();

        String line = null;
        try {
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                is.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

        return sb.toString();
    }

    public String connect()
    {
        HttpClient httpclient = new DefaultHttpClient();

        // Prepare a request object
        HttpPost htopost = new HttpPost("URL");
        htopost.setHeader(new BasicHeader("Authorization","Basic Og=="));

        try {

            JSONObject param = new JSONObject();
            param.put("PageSize",100);
            param.put("Userid",userId);
            param.put("CurrentPage",1);

            htopost.setEntity(new StringEntity(param.toString()));

            // Execute the request
            HttpResponse response;

            response = httpclient.execute(htopost);
            // Examine the response status
            // Get hold of the response entity
            HttpEntity entity = response.getEntity();

            if (entity != null) {

                // A Simple JSON Response Read
                InputStream instream = entity.getContent();
                String result = convertStreamToString(instream);

                // A Simple JSONObject Creation
                json = new JSONArray(result);

                // Closing the input stream will trigger connection release
                instream.close();
                return ""+response.getStatusLine().getStatusCode();
            }
        } catch (Exception e) {
            e.printStackTrace();
        }

        return null;
    }

    @Override
    protected String doInBackground(String... urls) {
        return connect();
    }

    @Override
    protected void onPostExecute(String status){
        try {

            if(status.equals("200"))
            {

                    Global.defaultMoemntLsit.clear();

                    for (int i = 0; i < json.length(); i++) {
                        JSONObject ojb = json.getJSONObject(i);
                        UserMomentModel u = new UserMomentModel();
                        u.setId(ojb.getString("Name"));
                        u.setUserId(ojb.getString("ID"));


                        Global.defaultMoemntLsit.add(u);
                    }




                            userAdapter = new UserAdapter(getActivity(), Global.defaultMoemntLsit);
                            recycleView.setAdapter(userMomentAdapter);
                            recycleView.setLayoutManager(mLayoutManager);
           }



        }
        catch (Exception e)
        {
            e.printStackTrace();

        }
    }
}

在Android中使用带有post参数的HttpClient和HttpPost

4 个答案: