我有一个对或错的列表。我想知道他们是否都是对还是错。
我的代码:
list1 = [False, True,False,False,True]
list2 = [False, True,False,True]
list3 = [False, False,False]
list4 = [True, True,True, True,True]
if sum(list1)==len(list1)|0:
print("Yes! all are either True or False")
else:
print("Not satisfied")
如果所有代码均为True,但如果所有代码均为False,我的代码就可以正常工作。如何检查是否全部为假
四个列表的预期输出:
list1 >> Not satisfied
list2 >> Not satisfied
list3 >> Yes! all are either True or False
list4 >> Yes! all are either True or False
答案 0 :(得分:3)
在这种情况下,您可以使用内置的all()
和any()
:
for lst in [list1, list2, list3, list4]:
if all(lst) or not any(lst): # if it isn't true that any are true, then all must be False
print("Yes! all are either True or False")
else:
print("Not satisfied")
输出:
Not satisfied
Not satisfied
Yes! all are either True or False
Yes! all are either True or False