如何使用Python Tkinter在一行中显示几个标签而在下一行中显示几个标签？

Question

我有一个程序，可在GUI屏幕上显示标签，但全部显示在一行中。我想在一行的第一个循环中显示所有标签，并在另一行显示第二个循环中的所有标签。代码如下：

from tkinter import *
import tkinter as tk

win = Tk()
win.title("Labels")
win.geometry("800x600+50+50")
win.config(bg='white')

label1=Label(win, text="All Labels", font=("Calibri",24,"bold"), bg='white', borderwidth=1, relief="solid")
label1.pack(pady=15)

for a in range(10):
    pre1=Label(win, text=("PIN",a), font=("Calibri",12), bg="white", borderwidth=1, relief="solid")
    pre1.pack(side=tk.LEFT)

for b in range(10):

    if (b%2==0):
        pre2=Label(win, text="OFF", font=("Calibri",12), bg="white", borderwidth=1, relief="solid")
        pre2.pack(side=tk.LEFT)
    else:
        pre3=Label(win, text="ON", font=("Calibri",12), bg="white", borderwidth=1, relief="solid")
        pre3.pack(side=tk.LEFT)

win.mainloop()

输出：

Answer 1

这应该有效：

from tkinter import *
import tkinter as tk

win = Tk()
win.title("Labels")
win.geometry("800x600+50+50")
win.config(bg='white')

label1=Label(win, text="All Labels", font=("Calibri",24,"bold"), bg='white', borderwidth=1, relief="solid")
label1.pack(pady=15)

lblframe = tk.Frame(win)
for a in range(10):
    pre1=Label(lblframe, text=("PIN",a), font=("Calibri",12), bg="white", borderwidth=1, relief="solid")
    pre1.grid(row=0, column=a)

for b in range(10):

    if (b%2==0):
        pre2=Label(lblframe, text="OFF", font=("Calibri",12), bg="white", borderwidth=1, relief="solid")
        pre2.grid(row=1, column=b)
    else:
        pre3=Label(lblframe, text="ON", font=("Calibri",12), bg="white", borderwidth=1, relief="solid")
        pre3.grid(row=1, column=b)

lblframe.pack()

win.mainloop()