我使用了以下查询:
SELECT TOP (3) no, co, cdate, year
FROM main_backup
WHERE (no = 41505)
ORDER BY cdate DESC
答案 0 :(得分:1)
您可以使用条件聚合和窗口函数:
select no,
max(case when seqnum = 1 then total end) as total_1,
max(case when seqnum = 1 then cdate end) as date_1,
max(case when seqnum = 2 then total end) as total_2,
max(case when seqnum = 2 then cdate end) as date_2,
max(case when seqnum = 3 then total end) as total_3,
max(case when seqnum = 3 then cdate end) as date_3
from (select t.*,
row_number() over (partition by no order by cdate desc) as seqnum
from t
) t
group by no