我在PyQT5中有一个网格,并且按钮可以通过QTextEdit添加更多行,我可以添加一个按钮来按每个QTextEdit值的降序对所有行进行排序吗?
UPD。有最少的代码现在如何工作
from PyQt5 import QtWidgets, QtGui
from PyQt5.QtCore import QTime, QTimer, QObject
from PyQt5.QtWidgets import QMainWindow, QApplication, QLCDNumber, QPushButton, QGridLayout, QLabel, QLineEdit, QTextEdit, QGroupBox
import sys
from somethingtestui import Ui_MainWindow
global rowcnt
rowcnt = 1
cntr = []
class mywindow(QtWidgets.QMainWindow):
def __init__(self):
super(mywindow, self).__init__()
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
self.ui.pushButton.clicked.connect(self.add)
self.ui.gridLayout.setRowMinimumHeight(50,50)
self.ui.gridLayout.setColumnMinimumWidth(50,50)
# self.sort = QPushButton('Sort')
# self.ui.gridLayout.addWidget(self.sort, 0, 2, 1, 1)
# self.sort.clicked.connect(self.sbtn)
self.ui.gridLayout.setVerticalSpacing(0)
def add(self):
global rowcnt
self.row = QTextEdit('')
self.delbtn = QPushButton('Delete row')
self.ui.gridLayout.addWidget(self.row, rowcnt, 0, 1, 1)
self.ui.gridLayout.addWidget(self.delbtn, rowcnt, 1, 1, 1)
w = self.ui.gridLayout.itemAtPosition(rowcnt,1).widget()
def delf(currow):
global rowcnt
rowcnt = rowcnt-1
number = self.ui.gridLayout.itemAtPosition(currow,1).widget()
number2 = self.ui.gridLayout.itemAtPosition(currow,0).widget()
number.deleteLater()
number2.deleteLater()
w.clicked.connect(lambda: delf(mrowcnt))
rowcnt = rowcnt+1
mrowcnt = rowcnt-1
和该用户界面
class Ui_MainWindow(object):
def setupUi(self, MainWindow):
MainWindow.setObjectName("MainWindow")
MainWindow.resize(800, 600)
self.centralwidget = QtWidgets.QWidget(MainWindow)
self.centralwidget.setObjectName("centralwidget")
self.gridLayoutWidget = QtWidgets.QWidget(self.centralwidget)
self.gridLayoutWidget.setGeometry(QtCore.QRect(70, 30, 441, 121))
self.gridLayoutWidget.setObjectName("gridLayoutWidget")
self.gridLayout = QtWidgets.QGridLayout(self.gridLayoutWidget)
self.gridLayout.setContentsMargins(0, 0, 0, 0)
self.gridLayout.setObjectName("gridLayout")
self.pushButton = QtWidgets.QPushButton(self.gridLayoutWidget)
self.pushButton.setObjectName("pushButton")
self.gridLayout.addWidget(self.pushButton, 0, 1, 1, 1)
self.textBrowser = QtWidgets.QTextEdit(self.gridLayoutWidget)
self.textBrowser.setObjectName("textBrowser")
self.gridLayout.addWidget(self.textBrowser, 0, 0, 1, 1)
MainWindow.setCentralWidget(self.centralwidget)
self.menubar = QtWidgets.QMenuBar(MainWindow)
self.menubar.setGeometry(QtCore.QRect(0, 0, 800, 21))
self.menubar.setObjectName("menubar")
MainWindow.setMenuBar(self.menubar)
self.statusbar = QtWidgets.QStatusBar(MainWindow)
self.statusbar.setObjectName("statusbar")
MainWindow.setStatusBar(self.statusbar)
self.retranslateUi(MainWindow)
QtCore.QMetaObject.connectSlotsByName(MainWindow)
def retranslateUi(self, MainWindow):
_translate = QtCore.QCoreApplication.translate
MainWindow.setWindowTitle(_translate("MainWindow", "MainWindow"))
self.pushButton.setText(_translate("MainWindow", "PushButton"))
现在,我考虑收集所有textedit文本并在列表中进行排序,但是之后该怎么做-我不知道。也许是它解决问题的愚蠢方法,但我现在没有其他方法。
答案 0 :(得分:0)
仅更新文本值比在布局中的小部件之间移动要容易得多。您可以调用QTextEdit.toPlainText()
来获取每个文本值作为字符串。将所有字符串放在列表中,对列表进行排序,然后在布局中的每个QTextEdit上使用QTextEdit.setText()
。
def sbtn(self):
text_edits = [self.ui.gridLayout.itemAt(i).widget() for i in range(self.ui.gridLayout.count()) if isinstance(self.ui.gridLayout.itemAt(i).widget(), QTextEdit)]
text = sorted([x.toPlainText() for x in text_edits], reverse=True)
for i in range(len(text)):
text_edits[i].setText(text[i])