如何打破这个while(true)循环?

时间:2020-02-16 18:01:07

标签: java while-loop break

嗨,我想打破这个循环,在两个if语句都为true时返回坐标。但是循环永远不会结束。 我该如何解决?

public static String[] positionQuery(int dim, Scanner test_in) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Provide origin and destination coordinates.");
        System.out.println("Enter two positions between A1-H8:");
        while(true) {
            String line = scanner.nextLine();
            String[] coordinates = line.split(" ");
            if(coordinates.length == 2) {
                String origin = coordinates[0];
                String dest = coordinates[1];
                if(validCoordinate(origin, dim) && validCoordinate(dest,dim)) {
                    return coordinates;
                }
            }
            System.out.println("ERROR: Please enter valid coordinate pair separated by space.");
        }
    }

我想我对validCoordinates有问题,因为我只是对validCoordinates有所了解,但找不到我做错的事情。

public static boolean validCoordinate(String coordinate, int dimension) {
        boolean isValidCoordinate;
        String [] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
        int [] numbers = new int [dimension];
        int one = 1;
        for(int i = 0; i < dimension; i++){
            numbers[i] = one + i;
        }
        for(int i = 0; i < dimension; i++){
            if((Character.toString(coordinate.charAt(0))).contains(alphabet[i])) {
                for(int j = 0; j < dimension; j++) {
                    if ((coordinate.substring(1)).contains(Integer.toString(numbers[j]))) {
                        return true;
                    }
                }
            }
        }

        return false;
    }

2 个答案:

答案 0 :(得分:3)

查看是否可行。我只是做了一个Boolean标志变量来退出while循环。一旦到达第二个if,就应该使该标志为假。

public static String[] positionQuery(int dim, Scanner test_in) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Provide origin and destination coordinates.");
        System.out.println("Enter two positions between A1-H8:");
        Boolean flag = true;
        while(flag) {
            String line = scanner.nextLine();
            String[] coordinates = line.split(" ");
            if(coordinates.length == 2) {
                String origin = coordinates[0];
                String dest = coordinates[1];
                if(validCoordinate(origin, dim) && validCoordinate(dest,dim)) {
                    flag = false;
                    return coordinates;
                }
            }
            System.out.println("ERROR: Please enter valid coordinate pair separated by space.");
        }
    }

答案 1 :(得分:2)

您的有效坐标不正确,它仅检查由字母数组中的维度参数指定的前几个值。

尝试一下

public static boolean validCoordinate(String coordinate, int dimension) {
        boolean isValidCoordinate;
        String [] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
        int [] numbers = new int [dimension];
        for(int i = 0; i < dimension; i++){
            numbers[i] = 1 + i;
        }
        if(Arrays.asList(alphabet).contains(Character.toString(coordinate.charAt(0)))) {
            for(int j = 0; j < dimension; j++) {
              if ((coordinate.substring(1)).contains(Integer.toString(numbers[j]))) {
                  return true;
              }
            }
        }
        return false;
    }

您绝对可以改进此代码,我将对您构成挑战。

这是相关的代表 https://repl.it/@Blakeinstein/question60251495

忍者编辑: 我建议您修改您的positionquery

public static String[] positionQuery(int dim) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Provide origin and destination coordinates.");
        System.out.println("Enter two positions between A1-H8:");
        while(true) {
            String line = scanner.nextLine();
            String[] coordinates = line.split(" ");
            if(coordinates.length == 2) {
                String origin = coordinates[0];
                String dest = coordinates[1];
                if(validCoordinate(origin, dim) && validCoordinate(dest,dim)) {
                    return coordinates;
                }
                else{
                  System.out.println("Coordinates are not valid");
                }
            }
            else{
              System.out.println("ERROR: Please enter valid coordinate pair separated by space.");
            }
        }
    }