pythoncom.PumpMessages()
据我所知,这条线基本上告诉程序永远等待。为了我的目的,它似乎工作。但是,我希望能够在给定正确刺激的情况下结束该计划。如何结束上述行,或停止程序进一步运行。
答案 0 :(得分:7)
根据这些docs,pythoncom.PumpMessages()
:
为当前线程提取所有消息,直到WM_QUIT消息为止。
因此,停止收集邮件的一种方法是使用ctypes库将{WMIQUIT邮件发送到邮件队列来调用PostQuitMessage:
ctypes.windll.user32.PostQuitMessage(0)
答案 1 :(得分:6)
以下是使用计时器线程退出应用程序的示例:
import win32api
import win32con
import pythoncom
from threading import Timer
main_thread_id = win32api.GetCurrentThreadId()
def on_timer():
win32api.PostThreadMessage(main_thread_id, win32con.WM_QUIT, 0, 0);
t = Timer(5.0, on_timer) # Quit after 5 seconds
t.start()
pythoncom.PumpMessages()
PostQuitMessage()
仅适用于主线程,但是主线程再次被阻止,因此它本身并不是很有用。只有在将自己的自定义消息处理挂钩到消息循环中时,才能使用它。
答案 2 :(得分:0)
我想通过Gregg和Boaz Yaniv扩展这两个答案。您通常会在单独的线程中运行阻塞代码,因此您需要将WM_QUIT发送到该线程。您应该使用Gregg所指出的PostQuitMessage,但这仅适用于当前线程。您不应该使用PostThreadMessage发送WM_QUIT(无法记住我在docs中看到的位置)。您可以在讨论" Why is there a special PostQuitMessage function?"中详细了解它。我认为首先将WM_CLOSE发送到线程会更好。
# if more hotkeys needs to be supported at the same time this class needs to be rewritten
class HotKey:
def __init__(self, modifier_key, virtual_key, callback):
self.hotkey_id = 1
# shared variable to pass thread id
self.pid = mpdummy.Value('l', 0)
# start checking hotkey press in new thread
self.process_pool = mpdummy.Pool()
self.process_pool.apply_async(HotKey.register, (self.hotkey_id, self.pid, modifier_key, virtual_key, callback, ))
self.process_pool.close()
# bind windows global hotkey
@staticmethod
def register(hotkey_id, pid, modifier_key, virtual_key, callback):
# set thread ID to shared variable
# Win API could also be used:
# ctypes.windll.Kernel32.GetCurrentThreadId()
pid.value = mpdummy.current_process().ident
# register hotkey with Win API
logging.getLogger('default').info("Registering hotkey with id " + str(hotkey_id) + " for key " + str(modifier_key) + " " + str(virtual_key))
if not ctypes.windll.user32.RegisterHotKey(None, hotkey_id, modifier_key, virtual_key):
logging.getLogger('default').info("Unable to register hotkey with id " + str(hotkey_id))
msg = ctypes.wintypes.MSG()
try:
# wait for a message - it doesn't return until some message arrives
while ctypes.windll.user32.GetMessageA(ctypes.byref(msg), None, 0, 0) != 0:
# WM_HOTKEY 0x0312
# https://msdn.microsoft.com/en-us/library/windows/desktop/ms646279(v=vs.85).aspx
if msg.message == 0x0312:
logging.getLogger('default').info("Pressed hotkey with id " + str(hotkey_id))
callback()
# WM_CLOSE
# https://msdn.microsoft.com/en-us/library/windows/desktop/ms632617(v=vs.85).aspx
elif msg.message == 0x0010:
# quit current thread
# WM_QUIT shouldn't be send with PostThreadMessageA therefore we send WM_CLOSE and quit inside thread.
# More info at:
# https://msdn.microsoft.com/en-us/library/windows/desktop/ms644945(v=vs.85).aspx
# https://blogs.msdn.microsoft.com/oldnewthing/20051104-33/?p=33453
ctypes.windll.user32.PostQuitMessage(0)
ctypes.windll.user32.TranslateMessage(ctypes.byref(msg))
ctypes.windll.user32.DispatchMessageA(ctypes.byref(msg))
finally:
logging.getLogger('default').info("Unregistering hotkey for id " + str(hotkey_id))
ctypes.windll.user32.UnregisterHotKey(None, hotkey_id)
def unregister(self):
# send WM_CLOSE signal to thread checking for messages
# WM_CLOSE 0x0010
# https://msdn.microsoft.com/en-us/library/windows/desktop/ms632617(v=vs.85).aspx
ctypes.windll.user32.PostThreadMessageA(self.pid.value, 0x0010, 0, 0)
# wait for thread to finish
self.process_pool.join()
我将它用于RegisterHotKey,但原理是一样的。这个类可以被称为:
# bind global hotkey for "pressing" start/split button
# MOD_ALT 0x0001
# VK_F12 0x7B
# https://msdn.microsoft.com/en-us/library/windows/desktop/ms646309(v=vs.85).aspx
# https://msdn.microsoft.com/en-us/library/windows/desktop/dd375731.aspx
self.hotkey = hotkey.HotKey(0x0001, 0x7B, self.special_key_pressed)
当你想结束等待消息时,请致电:
self.hotkey.unregister()