我想为我的应用程序实现Provider,经过一些研究后,我发现我必须为Data类实现ChangeNotifier才能在“天”更改时更新UI。
我见过人们在setter方法中编写notifyListeners(),但是总是针对单个属性,而不是列表。什么是正确的实现?
谢谢!
这是我的课程和清单:
class Data with ChangeNotifier {
List<Day> days = [
Day(
name: 'Monday',
transactions: [
Transaction(
isExpense: true,
name: 'Pizza',
transactionType: TransactionType.food,
amount: '120€',
),
Transaction(
isExpense: true,
name: 'EDEKA',
transactionType: TransactionType.payment,
amount: '120€',
),
],
),
Day(
name: 'Tuesday',
transactions: [
Transaction(
isExpense: true,
name: 'Sushi',
transactionType: TransactionType.food,
amount: '120€',
),
Transaction(
isExpense: true,
name: 'Lidl',
transactionType: TransactionType.payment,
amount: '120€',
),
Transaction(
isExpense: false,
name: 'Einkommen',
transactionType: TransactionType.payment,
amount: '120€',
),
],
),
];
}
答案 0 :(得分:3)
有2种添加和删除项目的方法。
void add(Day day) {
days.add(day);
notifyListeners();
}
void remove(int index) {
days.removeAt(index);
notifyListeners();
}
答案 1 :(得分:3)
Todo App是处理List<Taks>
的很好的例子
您可以参考https://dev.to/shakib609/create-a-todos-app-with-flutter-and-provider-jdh
完整的示例github代码https://github.com/shakib609/todos-flutter/tree/master/lib
代码段
class Task {
String title;
bool completed;
Task({@required this.title, this.completed = false});
void toggleCompleted() {
completed = !completed;
}
}
class TodosModel extends ChangeNotifier {
final List<Task> _tasks = [];
UnmodifiableListView<Task> get allTasks => UnmodifiableListView(_tasks);
UnmodifiableListView<Task> get incompleteTasks =>
UnmodifiableListView(_tasks.where((todo) => !todo.completed));
UnmodifiableListView<Task> get completedTasks =>
UnmodifiableListView(_tasks.where((todo) => todo.completed));
void addTodo(Task task) {
_tasks.add(task);
notifyListeners();
}
void toggleTodo(Task task) {
final taskIndex = _tasks.indexOf(task);
_tasks[taskIndex].toggleCompleted();
notifyListeners();
}
void deleteTodo(Task task) {
_tasks.remove(task);
notifyListeners();
}
}
工作演示