我有实体
Cache::tags(['people', 'artists'])->put('John', $john, $minutes);
Cache::tags(['people', 'authors'])->put('Anne', $anne, $minutes);
此实体的超类
@Entity
@Table(
name = SomeEntity.TABLE_NAME,
uniqueConstraints = {@UniqueConstraint(columnNames = {"first", "second"})}
)
public class SomeEntity extends SomeSuperEntity {
public static final String TABLE_NAME = "SomeEntity";
public SomeEntity() {
}
public SomeEntity(String first, String second, Integer third) {
super(first, second, third);
}
}
第二超类
@MappedSuperclass
public abstract class SomeSuperEntity extends SomeSuperAbstractEntity {
@Column(nullable = false)
private String first;
@Column(nullable = false)
private String second;
protected SomeSuperEntity () {
}
protected SomeSuperEntity (String first, String second, Integer third) {
super(third);
this.first= first;
this.second= second;
}
}
我有这2种方法,第一种-用于查找实体
@MappedSuperclass
public abstract class SomeSuperAbstractEntity {
@Column(nullable = false)
private Integer third;
protected SomeSuperAbstractEntity () {
}
protected SomeSuperAbstractEntity (Integer third) {
this.third= third;
}
}
第二个获取实体名称到hql
public <T extends SomeSuperEntity > Optional<T> findByFirstAndSecond(String first, String second, Class<T> tClass) {
String hql = String.format("FROM %s E WHERE E.first = :first AND E.second = :second", getTable(tClass));
return jpaApi.em().createQuery(hql, tClass)
.setParameter("first", first)
.setParameter("second", second)
.getResultList().stream().findAny();
}
当我尝试调用findByFirstAndSecond(“ 1”,“ 2”,SomeEntity.class)时,我遇到了错误
[错误] ciSomeMethod-错误:org.hibernate.hql.internal.ast.QuerySyntaxException:未映射SomeEntity [FROM SomeEntity E WHERE E.first =:first AND E.second =:second] < / strong>
答案 0 :(得分:1)
您是否已定义要在应用程序上下文中扫描的软件包?
<property name="packagesToScan">
<list>
<value>com.package_to_someentity</value>
</list>
</property>
或者,在您hibernate.cfg.xml
中定义它
<hibernate-configuration>
<session-factory>
<mapping class="com.package_to_someentity.SomeEntity" />
</session-factory>
</hibernate-configuration>