Question

首先，非常感谢https://stackoverflow.com/对我一生的编码贡献，这是我对https://stackoverflow.com/的第一个疑问

这是我的问题

这是我的前端json.js文件，可以正常工作：

const Subjects=[
    {id:1,  selectGrade: "LKG", GradeName: "LKG",
        Detail: [
        { Subject: "English", Content: "Private"},
        { Subject: "Math", Content: "Private"}
    ]},
    {id:2,  selectGrade: "UKG", GradeName: "UKG",
        Detail: [
        { Subject: "English", Content: "Private"},
        { Subject: "Math", Content: "Private"},
        { Subject: "Punjabi", Content: "Private"}
    ]},
    {id:3,  selectGrade: "class-1", GradeName: "1st",
        Detail: [
        { Subject: "English", Content: "PSEB"},
        { Subject: "Math", Content: "PSEB"},
        { Subject: "Punjabi", Content: "Private"},
        { Subject: "Hindi", Content: "Private"},
        { Subject: "EVS", Content: "Private"},
        { Subject: "Computer Science", Content: "Private"},
        { Subject: "General Knowledge", Content: "Private"},
        { Subject: "Drawing", Content: "Private"}
    ]}
];
export default Subjects;

这是我在后端{在 subject_details 表 subject_id 是外键}中的api的代码

const express = require('express');
const Router = express.Router();
Router.get("/", (req, res)=>{
        db.query("SELECT GradeName, Subject, Content FROM subjects INNER JOIN subject_details ON subjects.subject_id = subject_details.subject_id", (err, rows, fields) =>{
        if(!err)
            {res.send(rows);}
        else
            {console.log(err);}
    })
})
module.exports = Router;

它会给我这样平坦的结果：

[{"GradeName":"LKG","Subject":"English","Content":"Private"},{"GradeName":"LKG","Subject":"Math","Content":"Private"},{"GradeName":"UKG","Subject":"English","Content":"Private"},{"GradeName":"UKG","Subject":"Math","Content":"Private"},{"GradeName":"UKG","Subject":"Punjabi","Content":"Private"}]

我想要结果作为我的json文件。我尝试了太多，但在互联网上没有任何有用的发现。

请帮助我

预先感谢

在节点js中使用mysql创建嵌套的json api并表达

0 个答案: