Question

我遇到了解决嵌套xml问题的问题。有人可以告诉我，如果我遗失了什么 body标记可以包含任何Jaxb anotated obj 我是否必须创建一个自定义适配器来编组/解组这样的xml？

输入XML

<?xml version="1.0" encoding="UTF-8"?>
<serviceRq xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="serviceRq">
  <body>   
    <createRq>
       <id>1234</id>
    </createRq>
  </body>
</serviceRq>

我的Jaxb注释类是：

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "serviceRq")
public class ServiceRq{    
    private Object body;
    <!-- getters and setters omitted-->
}

这里，body可以是任何jaxb注释对象，在本例中是CreateRq。

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "createRq")
public class CreateRq{    
    private String id;
    <!-- getters and setters omitted-->
}

我正在寻找一种通用方法来支持输入xml体中任何带有Jaxb注释的对象。

Answer 1

您可以使用@XmlAnyElement(lax=true)和XmlAdapter来处理此用例：

<强> ServiceRq

import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "serviceRq")
public class ServiceRq{    

    @XmlJavaTypeAdapter(value=BodyAdapter.class)
    private Object body;
    // getters and setters omitted
}

<强> BodyAdapter

import javax.xml.bind.annotation.adapters.XmlAdapter;

public class BodyAdapter extends XmlAdapter<Body, Object>{

    @Override
    public Object unmarshal(Body v) throws Exception {
        return v.getValue();
    }

    @Override
    public Body marshal(Object v) throws Exception {
        Body body = new Body();
        body.setValue(v);
        return body;
    }

}

<强>车身

import javax.xml.bind.annotation.XmlAnyElement;

public class Body {

    private Object value;

    @XmlAnyElement(lax=true)
    public Object getValue() {
        return value;
    }

    public void setValue(Object value) {
        this.value = value;
    }

}

<强> CreateRq

import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "createRq")
public class CreateRq{    
    private String id;
    // getters and setters omitted
}

<强>演示

import java.io.File;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(ServiceRq.class);
        System.out.println(jc);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        ServiceRq serviceRq = (ServiceRq) unmarshaller.unmarshal(new File("input.xml"));

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(serviceRq, System.out);

    }

}

了解更多信息

Answer 2

您可以使用@XmlAnyElement(lax=true)和EclipseLink JAXB (MOXy)中的@XmlPath扩展来处理此用例（注意：我是MOXy的主管）。对于适用于任何JAXB实现（Metro，MOXy，JaxMe等）的方法，请参阅：Jaxb complex xml unmarshall。

<强> ServiceRq

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAnyElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;

import org.eclipse.persistence.oxm.annotations.XmlPath;

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "serviceRq")
public class ServiceRq{    

    @XmlPath("body/createRq")
    @XmlAnyElement(lax=true)
    private Object body;
    // getters and setters omitted
}

<强> CreateRq

import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "createRq")
public class CreateRq{    
    private String id;
    // getters and setters omitted
}

<强>演示

import java.io.File;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(ServiceRq.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        ServiceRq serviceRq = (ServiceRq) unmarshaller.unmarshal(new File("input.xml"));

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(serviceRq, System.out);

    }
}

<强> jaxb.properties

要将MOXy用作JAXB提供程序，必须在与域模型相同的程序包中包含名为jaxb.properties的文件，并带有以下条目：

javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory

了解更多信息

Jaxb复杂xml unmarshal

2 个答案: