Question

在这是XML文件中，我必须在列表中获取所有Source dll。我正在尝试以下查询。

Dim appManifest As String = New System.IO.StreamReader（Application.GetResourceStream（New System.Windows.Resources.StreamResourceInfo（e.Result，Nothing），New Uri（“AppManifest.xaml”，UriKind.Relative））。流）.ReadToEnd（）

Dim deploymentRoot As XElement = XDocument.Parse（appManifest）.Root ** Dim parts作为List（Of XElement）=（来自assemblyParts In _ deploymentRoot.Elements（）。Elements（）选择assemblyParts）。ToList（）**

但是patrs包含count.It不是列表。我怎么能这样做？

以下是XML文档。

<Deployment xmlns="http://schemas.microsoft.com/client/2007/deployment" 
            RuntimeVersion="4.0.50826.0">
    <Deployment.OutOfBrowserSettings>
        <OutOfBrowserSettings ShortName="WebPortalUI Application" 
                              EnableGPUAcceleration="False" 
                              ShowInstallMenuItem="True">
            <OutOfBrowserSettings.Blurb>
                WebPortalUI Application on your desktop; 
                at home, at work or on the go.
            </OutOfBrowserSettings.Blurb>
            <OutOfBrowserSettings.WindowSettings>
                <WindowSettings Title="WebPortalUI Application" 
                                Height="400" Width="928" />
            </OutOfBrowserSettings.WindowSettings>
            <OutOfBrowserSettings.Icons />
        </OutOfBrowserSettings>
    </Deployment.OutOfBrowserSettings>

    <Deployment.Parts>
        <AssemblyPart x:Name="WebPortalUI" 
                      Source="WebPortalUI.dll" />
        <AssemblyPart x:Name="System.ComponentModel.Composition"
                      Source="System.ComponentModel.Composition.dll" />
        <AssemblyPart x:Name="System.ComponentModel.Composition.Initialization"
                      Source="System.ComponentModel.Composition.Initialization.dll" />
        <AssemblyPart x:Name="System.ComponentModel.DataAnnotations"
                      Source="System.ComponentModel.DataAnnotations.dll" />
        <AssemblyPart x:Name="System.Windows.Controls.Data.Input"
                      Source="System.Windows.Controls.Data.Input.dll" />
        <AssemblyPart x:Name="System.Windows.Controls.Navigation"
                      Source="System.Windows.Controls.Navigation.dll" />
        <AssemblyPart x:Name="System.Xml.Linq" 
                      Source="System.Xml.Linq.dll" />
        <AssemblyPart x:Name="System.Xml.Serialization"
                      Source="System.Xml.Serialization.dll" />
        <AssemblyPart x:Name="Telerik.Windows.Controls"
                      Source="Telerik.Windows.Controls.dll" />
        <AssemblyPart x:Name="Telerik.Windows.Controls.Docking"
                      Source="Telerik.Windows.Controls.Docking.dll" />
        <AssemblyPart x:Name="Telerik.Windows.Controls.GridView"
                      Source="Telerik.Windows.Controls.GridView.dll" />
        <AssemblyPart x:Name="Telerik.Windows.Controls.Input"
                      Source="Telerik.Windows.Controls.Input.dll" />
        <AssemblyPart x:Name="Telerik.Windows.Controls.Navigation"
                      Source="Telerik.Windows.Controls.Navigation.dll" />
        <AssemblyPart x:Name="Telerik.Windows.Data" 
                      Source="Telerik.Windows.Data.dll" />
        <AssemblyPart x:Name="ViewModel" 
                      Source="ViewModel.dll" />
        <AssemblyPart x:Name="System.Windows.Data" 
                      Source="System.Windows.Data.dll" />
    </Deployment.Parts>

</Deployment>

Answer 1

您是否尝试过使用xpath？查询将类似于// AssemblyPart / [Source]

XPath general：http://www.w3schools.com/xpath/default.asp

XPath＆amp; .Net：http://www.developer.com/net/net/article.php/3383961/NET-and-XML-XPath-Queries.htm

欢呼声

Answer 2

使用LINQ的答案是： http://forums.asp.net/t/1681678.aspx/1

从那里复制：

Dim assemblySources  = From aPart In XDocument.Load().Descendants("AssemblyPart") select a.Attribute("Source").Value  
For Each item As string In assemblySources 
  Console.WriteLine(item)  
Next

需要LINQ查询来读取返回列表的XML文件

2 个答案: