Question

+----+---------+-----------+---------------------+-----------+-----------+
| id | user_id | foo_id    | created_at          | active    |type       |
+----+---------+-----------+---------------------+-----------+-----------+
|  1 |       1 |         1 | 2011-05-10 13:12:35 |         1 | 2         |
|  7 |       5 |         2 | 2011-05-10 14:45:04 |         1 | 1         |
|  4 |       4 |         2 | 2011-05-10 13:24:45 |         1 | 2         |
|  8 |       6 |         2 | 2011-05-16 14:53:03 |         1 | 1         |
|  9 |       7 |         2 | 2011-05-16 14:55:11 |         1 | 0         |
+----+---------+-----------+---------------------+-----------+-----------+

这是django中的UserMapper模型。我想写一个查询：

获取foo_id = 2 and type=0以及user_id = 6;的所有结果的所有user_id 说;

select * from table where user_id = 6 and (foo_id=2 and type=6) // Such sort of query

如何在django查询集中进行..

Answer 1

如果您的意思是user_id=6 and type=6 and food_id=2，那么只需使用：

UserMapper.objects.filter(user_id=6, type=6, food_id=2)

如果您的意思是{user_id=6）or（type=6 and food_id=2），则可以使用Q对象：

from django.db.models import Q
UserMapper.objects.filter(Q(user_id=6) | Q(type=6, food_id=2))

在此处详细了解Q对象：http://docs.djangoproject.com/en/dev/topics/db/queries/#complex-lookups-with-q-objects

Answer 2

UserMapper.objects.filter(user_id=6).filter(food_id=2).filter(type=6)

Answer 3

UserMapper.objects.filter(user=user).filter(foo=foo).filter(type=0)，

其中user是User对象，ID为6，foo为Foo，ID为2，而{0}可能更好Type.SOMETHING而不是仅仅使用0

如何在django queryset中解决这个特定的查询

3 个答案: