我有一个这样的数据框:
Interesting genre_1 probabilities
1 no Empty 0.251306
2 yes Empty 0.042043
3 no Alternative 5.871099
4 yes Alternative 5.723896
5 no Blues 0.027028
6 yes Blues 0.120248
7 no Children's 0.207213
8 yes Children's 0.426679
9 no Classical 0.306316
10 yes Classical 1.044135
我想根据有趣的一列对同一类别执行GINI索引。之后,我想在新的pandas栏中添加这样的值。
这是获取基尼系数的函数:
#Gini Function
#a and b are the quantities of each class
def gini(a,b):
a1 = (a/(a+b))**2
b1 = (b/(a+b))**2
return 1 - (a1 + b1)
编辑*对不起,我最终想要的数据框出现错误。选择prob(A)和prob(B)时,有趣与否无关紧要,但基尼分数将相同,因为它将衡量我们将一首歌曲归类为有趣与否的程度。因此,如果概率在50/50%左右,则意味着基尼分数将达到最大值(0.5),这是因为同样有可能会被错误地选择是否感兴趣。
因此对于前两行,基尼索引将为:
a=no; b=Empty -> gini(0.251306, 0.042043)= 0.245559831601612
a=yes; b=Empty -> gini(0.042043, 0.251306)= 0.245559831601612
然后我想得到类似的东西:
Interesting genre_1 percentages. GINI INDEX
1 no Empty 0.251306 0.245559831601612
2 yes Empty 0.042043 0.245559831601612
3 no Alternative 5.871099 0.4999194135183881
4 yes Alternative 5.723896. 0.4999194135183881
5 no Blues 0.027028 ..
6 yes Blues 0.120248
7 no Children's 0.207213
8 yes Children's 0.426679
9 no Classical 0.306316 ..
10 yes Classical 1.044135 ..
答案 0 :(得分:1)
我不确定Interesting
列如何参与所有这些工作,但是我强烈建议您使用numpy.where()
来创建新列。语法类似于:
import numpy as np
df['GINI INDEX'] = np.where(__condition__,__what to do if true__,__what to do if false__)
答案 1 :(得分:1)
好的,我想我知道你的意思。如果兴趣值是“是”或“否”,则下面的代码无关紧要。但是,您想要的是根据该行的有趣值中的值,以两种不同的方式为每一行计算GINI系数。因此,如果有趣==否,则结果为0.5,因为a == b。但是,如果有趣的是“是”,则需要使用a =概率[i]和b =概率[i + 1]。因此,请跳过本节以获取下面的更新代码。
import pandas as pd
df = pd.read_csv('df.txt',delim_whitespace=True)
probs = df['probabilities']
def ROLLING_GINI(probabilities):
a1 = (probabilities[0]/(probabilities[0]+probabilities[0]))**2
b1 = (probabilities[0]/(probabilities[0]+probabilities[0]))**2
res = 1 - (a1 + b1)
yield res
for i in range(len(probabilities)-1):
a1 = (probabilities[i]/(probabilities[i]+probabilities[i+1]))**2
b1 = (probabilities[i+1]/(probabilities[i]+probabilities[i+1]))**2
res = 1 - (a1 + b1)
yield res
df['GINI'] = [val for val in ROLLING_GINI(probs)]
print(df)
这是真正的麻烦开始的地方,因为如果我正确理解了您的想法,那么您将无法计算最后的GINI值,因为您的数据框不允许这样做。这里重要的一点是,数据框中最后一个有趣的值是“是”。这意味着我必须使用a =概率[i]和b =概率[i + 1]。但是您的数据框没有行号11。您有10行,在第i == 10行上,您需要在第11行中有一个概率来计算GINI系数。因此,为了使您的想法生效,最后一个有趣的值必须为'no',否则您总是会遇到索引错误。
反正这是代码:
import pandas as pd
df = pd.read_csv('df.txt',delim_whitespace=True)
def ROLLING_GINI(dataframe):
probabilities = dataframe['probabilities']
how_to_calculate = dataframe['Interesting']
for i in range(len(dataframe)-1):
if how_to_calculate[i] == 'yes':
a1 = (probabilities[i]/(probabilities[i]+probabilities[i+1]))**2
b1 = (probabilities[i+1]/(probabilities[i]+probabilities[i+1]))**2
res = 1 - (a1 + b1)
yield res
elif how_to_calculate[i] == 'no':
a1 = (probabilities[i]/(probabilities[i]+probabilities[i]))**2
b1 = (probabilities[i]/(probabilities[i]+probabilities[i]))**2
res = 1 - (a1 + b1)
yield res
GINI = [val for val in ROLLING_GINI(df)]
print('All GINI coefficients: %s'%GINI)
print('Length of all calculatable GINI coefficients: %s'%len(GINI))
print('Number of rows in the dataframe: %s'%len(df))
print('The last Interesting value is: %s'%df.iloc[-1,0])
编辑第三个(对不起,很晚才实现):
因此,如果我正确应用索引,它确实可以工作。问题是我想使用 Next 概率,而不是前一个概率。所以它是a =概率[i-1]和b =概率[i]
import pandas as pd
df = pd.read_csv('df.txt',delim_whitespace=True)
def ROLLING_GINI(dataframe):
probabilities = dataframe['probabilities']
how_to_calculate = dataframe['Interesting']
for i in range(len(dataframe)):
if how_to_calculate[i] == 'yes':
a1 = (probabilities[i-1]/(probabilities[i-1]+probabilities[i]))**2
b1 = (probabilities[i]/(probabilities[i-1]+probabilities[i]))**2
res = 1 - (a1 + b1)
yield res
elif how_to_calculate[i] == 'no':
a1 = (probabilities[i]/(probabilities[i]+probabilities[i]))**2
b1 = (probabilities[i]/(probabilities[i]+probabilities[i]))**2
res = 1 - (a1 + b1)
yield res
GINI = [val for val in ROLLING_GINI(df)]
print('All GINI coefficients: %s'%GINI)
print('Length of all calculatable GINI coefficients: %s'%len(GINI))
print('Number of rows in the dataframe: %s'%len(df))
print('The last Interesting value is: %s'%df.iloc[-1,0])