我需要知道symfony项目中的数据库名称和数据库服务器名称。如何在symfony中使用编程方式访问当前数据库连接设置(使用Doctrine)?
答案 0 :(得分:22)
假设您将EntityManager设为$this->em
从Symfony2获取Doctrine数据库名称:
$this->em->getConnection()->getDatabase();
从Symfony2获取Doctrine主机名(服务器名称):
$this->em->getConnection()->getHost();
您可以从连接中访问许多其他参数,例如username
,port
和password
。有关详细信息,请参阅connection class
答案 1 :(得分:6)
例如:
foreach(Doctrine_Manager::getInstance()->getConnections() as $connection){
$conn = $connection->getOptions();
preg_match('/host=(.*);/', $conn['dsn'], $host);
var_dump($host);
}
答案 2 :(得分:2)
特定conexion的dsn中的dbname:
databases.yml里
all:
conexion1:
class: sfDoctrineDatabase
param:
dsn: 'mysql:host=localhost;dbname=basegestion1'
username: miusuario
password: ********
conexion2:
class: sfDoctrineDatabase
param:
dsn: 'mysql:host=localhost;dbname=baseestadisticas1'
username: miusuario
password: ********
在行动中:
$mConexion1Options = Doctrine_Manager::getInstance()->getConnection('conexion1')->getOptions();
preg_match('/dbname=(.*)/', $mConexion1Options['dsn'], $mDbConexion1);
然后,dbname为:
echo $mDbConexion1[1]; //basegestion1
答案 3 :(得分:1)
使用此代码:
$myConnection = Doctrine_Manager::getInstance()->getConnection('doctrine')->getOptions();
$dsnInfo = $this->parseDsn($myConnection['dsn']);
$settings = array();
$settings['dbUser'] = (string) $myConnection["username"];
$settings['dbPassword'] = (string) $myConnection["password"];
$settings['dbHost'] = (string) $dsnInfo["host"];
$settings['dbName'] = (string) $dsnInfo['dbname'];
private function parseDsn ($dsn)
{
$dsnArray = array();
$dsnArray['phptype'] = substr($dsn, 0, strpos($dsn, ':'));
preg_match('/dbname = (\w+)/', $dsn, $dbname);
$dsnArray['dbname'] = $dbname[1];
preg_match('/host = (\w+)/', $dsn, $host);
$dsnArray['host'] = $host[1];
return $dsnArray;
}
答案 4 :(得分:0)
试试这个
$conn = Doctrine_Manager::getInstance()->getConnection('doctrine')->getOptions();
$dns_array = split(';', $conn['dsn']);
preg_match('/host=(.*);/', $dns_array, $dbhost);
preg_match('/dbname=(.*)/', $dns_array, $dbname);
$dbname = $dbname;
$dbhost = $dbhost;
$dbuser = $conn['username'];
$dbpass = $conn['password'];
<强>更新强>
作为Function split() is deprecated
所以这是推荐的方式。
$dns_array = explode(';', $conn['dsn']);
preg_match('/host=(.*)/', $dns_array[0], $dbhost);
preg_match('/dbname=(.*)/', $dns_array[2], $dbname);
$dbhost = $dbhost[1];
$dbname = $dbname[1];
$dbuser = $conn['username'];
$dbpass = $conn['password'];