session_start();
if(!$_SESSION['user_id'])
{
$_SESSION['user_id'] = rand(1, 1000000);
include 'database_connect.php';
mysql_query('INSERT INTO product_views (user_session_id)
VALUES
('.$_SESSION['user_id'].')');
}
$productid = $_GET['name'];
$query = 'SELECT * FROM product_views WHERE user_session_id = '.$_SESSION['user_id'].'';
$result = mysql_query($query);
while ($row = mysql_fetch_array($result))
{
mysql_query('UPDATE product_views SET modelNumber="'.$productid.'" WHERE user_session_id="'.$_SESSION['user_id'].'"');
}
我的字段modelNumber设置为null,我通过上一个查询执行更新。 您认为由于默认值为null,因此不允许插入吗?
我的表结构:
CREATE TABLE `product_views` (
`id` int(10) DEFAULT NULL,
`user_session_id` int(11) DEFAULT NULL,
`product_id` varchar(100) DEFAULT NULL,
`view_date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`modelNumber` varchar(...
答案 0 :(得分:2)
我很困惑:
$query = 'SELECT * FROM product_views WHERE user_session_id = '.$_SESSION['user_id'].'';
$result = mysql_query($query);
while ($row = mysql_fetch_array($result))
{
mysql_query('UPDATE product_views SET modelNumber="'.$productid.'" WHERE user_session_id="'.$_SESSION['user_id'].'"');
}
如果您甚至没有使用$row
?
修改 :我认为这是您真正想要做的事情:
session_start();
if(!$_SESSION['user_id'])
{
// Get the user ID
$_SESSION['user_id'] = rand(1, 1000000);
require_once('database_connect.php');
// Get the model number and escape it to prevent SQL injection
$model_number = mysql_real_escape_string($_GET['name']);
// Insert a row that associates the user_id with the model number
mysql_query("INSERT INTO product_views (user_session_id,modelNumber) VALUES('{$_SESSION['user_id']}', '$model_number')");
}