Question

我尝试做一些条件，当我设置文本字段而不是单选按钮时，我将得到一个PHP错误。 ................................................... ................................................... ......................................

这是我的代码：

<form method="post">
   <input type="text" name="name">
   <input type="radio" name="gender" value="female">Female
   <input type="radio" name="gender" value="male">Male
   <input type="radio" name="gender" value="other">Other
   <input type="submit">
</form>

<?php

   $name = $nameErr = $gender = $genderErr = '';

   if ($_SERVER["REQUEST_METHOD"] == "POST") {

       if ($_POST['name'] == '' || $_POST['gender'] == '') {
          echo('all filed');
       }
       else {

          if (empty($_POST["name"])) {
             $nameErr = "Name is required";
          } else {
             $name = $_POST["name"];
          }
          if (empty($_POST["gender"])) {
             $genderErr = "Gender is required";
          } else {
             $gender = $_POST["gender"];
          }

       }

    }

  echo $name. ' ' .$gender;
?>

Answer 1

尝试：

if ((isset($_POST['name']) && $_POST['name'])  == '' || (isset($_POST['gender']) && $_POST['gender'] == '')) {
    echo('all filed');
}

如果未设置$_POST['gender']，则必须放置条件。您可以使用：

调试代码

echo "<pre>";
print_r($_POST);
exit;

Answer 2

根据您的代码，请使用以下条件

if (isset($_POST["name"]) && $_POST["name"] != "") {
    $name = $_POST["name"];  
} else {
    $nameErr = "Name is required";
}
if (isset($_POST["gender"]) && $_POST["gender"] != "") {
   $gender = $_POST["gender"];  
} else {
   $genderErr = "Gender is required";
}

Answer 3

在检查“名称”和“性别”字段时，情况不正确。您在条件中指定了“ OR（||）”，因此这意味着任何字段为空，它将返回true。您的情况如下：

if ($_POST['name'] == '' || $_POST['gender'] == '') {
    echo('all filed');
}

将其更改为：

 if ($_POST['name'] == '' && $_POST['gender'] == '') {
    echo('all filed');
 }

希望您的问题能得到解决。

Answer 4

尝试下面的代码，问题是您试图在条件之外打印值。

if ($_SERVER["REQUEST_METHOD"] == "POST") {

    if (empty($_POST['name']) || empty($_POST['gender'])) {
        echo('all filed');
    }
    else {

        if (empty($_POST["name"])) {
            $nameErr = "Name is required";
        }
        else {
            $name = $_POST["name"];
        }

        if (empty($_POST["gender"])) {
            $genderErr = "Gender is required";
        }
        else {
            $gender = $_POST["gender"];
        }

        echo $name . ' ' . $gender;
    }

}

Answer 5

更改此内容：

<form method="post">
<input type="text" name="name">
<input type="radio" name="gender" value="female">Female
<input type="radio" name="gender" value="male">Male
<input type="radio" name="gender" value="other">Other
<input type="submit">
</form>

对此：

<form method="post">
<input type="text" name="name">
<input type="radio" name="gender"  value="female" checked>Female
<input type="radio" name="gender" value="male">Male
<input type="radio" name="gender" value="other">Other
<input type="submit">
</form>

我未设置单选按钮时出现错误

5 个答案: