如何使用Python抓取方式下载zip文件?

时间:2020-02-05 11:02:55

标签: python python-3.x web-scraping

我想下载this链接的压缩文件。我尝试了各种方法,但是我做不到。

url = "https://www.cms.gov/apps/ama/license.asp?file=http://download.cms.gov/Research-Statistics-Data-and-Systems/Statistics-Trends-and-Reports/Medicare-Provider-Charge-Data/Downloads/Medicare_National_HCPCS_Aggregate_CY2017.zip"

# downloading with requests

# import the requests library
import requests


# download the file contents in binary format
r = requests.get(url)

# open method to open a file on your system and write the contents
with open("minemaster1.zip", "wb") as code:
    code.write(r.content)


# downloading with urllib

# import the urllib library
import urllib

# Copy a network object to a local file
urllib.request.urlretrieve(url, "minemaster.zip")

任何人都可以帮助我解决这个问题。

1 个答案:

答案 0 :(得分:0)

他们正在使用某些接受/拒绝机制,因此您需要将此参数添加到url:

url = 'http://download.cms.gov/Research-Statistics-Data-and-Systems/Statistics-Trends-and-Reports/Medicare-Provider-Charge-Data/Downloads/Medicare_National_HCPCS_Aggregate_CY2017.zip?agree=yes&next=Accept'
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