Question

我尝试使用下面的C＃代码调用Azure的Computer Vision API，但收到以下响应：

{"code":"404","message":"Resource not found"}

有什么建议可以完成这项工作吗？

using System;
using System.IO;
using System.Threading.Tasks;
using AzureFunctions.Extensions.CognitiveServices.Bindings.Vision.Analysis;
using Microsoft.Azure.WebJobs;
using Microsoft.Azure.WebJobs.Host;
using Microsoft.Extensions.Logging;
using Microsoft.WindowsAzure.Storage.Table;

namespace myCognitiveFunction
{
    public static class myCognitiveFunction
    {
        [FunctionName("myCognitiveFunction")]
        public static async Task RunAsync(

            [BlobTrigger("images/{name}", Connection = "storageAccount")]Stream myBlob,
            [VisionAnalysis(VisionKey = "Key", VisionUrl = "Url")]VisionAnalysisClient visionClient,
            [Table("VisionAnalysis", Connection = "storageAccount")]IAsyncCollector<VisionResult> results,
            string name, ILogger log)
        {
            var request = new VisionAnalysisRequest(myBlob);
            var result = await visionClient.AnalyzeAsync(request);
            var visionResult = new VisionResult(Guid.NewGuid().ToString(), "VisionAnalysis") { ResultJson = result.ToString() };

            await results.AddAsync(visionResult);
            log.LogInformation($"Results: {result.ToString()}");
        }
    }
    public class VisionResult : TableEntity
    {

        public VisionResult(string id, string partitionKey)
        {
            this.RowKey = id;
            this.PartitionKey = partitionKey;
        }

        public string ResultJson { get; set; }

    }
}

网址：https://mycognitive1000.cognitiveservices.azure.com/

Answer 1

首先，欢迎来到SO！看来您已经从文档中复制了代码，而没有替换服务工作所需的占位符storageAccount，Key，Url...。例如，在您的情况下，在您的问题下发布的URL应该进入VisionUrl属性中，如下所示：

[VisionAnalysis(VisionKey = "YOUR_KEY", VisionUrl = "mycognitive1000.cognitiveservices.azure.com")]

存储帐户是一个Azure Blob Storage连接字符串。至于Vision Key和Url，您可以在官方文档的Computer Vision API上找到不错的教程和文档。本教程还介绍了如何将这些参数写在单独的配置文件中，这是最佳实践。

Microsoft计算机视觉API返回404资源未找到

1 个答案: