Question

我有一个查询，我想根据特定条件为每个主键更新一个值。例如，对于该特定项目，无论TYPE是“ ASBESTOS”还是不存在TYPE“ CONTIN”，id都希望将“ ASBESTOS”更改为“ CONTIN”。

我已经在下面的查询中实现了此目的，但是即使将CONTIN已经存在，这也会将整个总体ASBESTOS值更新为CONTIN，基本上会产生重复的值。仅在CONTIN尚不存在时添加。也许Windows函数将起作用，以便它查看每个单独的项目，但是出现语法错误。谢谢您的帮助！

 SELECT PROJECT, 
 CASE WHEN TYPE = 'ASBESTOS' AND TYPE NOT IN 'CONTIN' THEN 'CONTIN' ELSE TYPE END AS TYPE, 
 SUM(OBLIGATION) AS OBS 
 FROM OBS_MASTER
 WHERE PROJECT = '074190'
 GROUP BY PROJECT, TYPE;

 Original:

 PROJECT      TYPE          OBS           
 074190      ASBESTOS     26326.99     
 074190        CM             0 

 Current Result:
 PROJECT      TYPE         OBS            
 074190        CM           0               
 074190      CONTIN      26326.99

Answer 1

如果我理解正确，则可以使用窗口函数计算每个项目的“ CONTIN”数，然后将该信息用作聚合键：

SELECT PROJECT, 
       (CASE WHEN NUM_CONTIN = 0 AND TYPE = 'ASBESTOS' THEN 'CONTIN' ELSE TYPE
        END) as TYPE
       SUM(OBLIGATION) AS OBS 
FROM (SELECT om.*,
             SUM(CASE WHEN TYPE = 'CONTIN' THEN 1 ELSE 0 END) OVER (PARTITION BY PROJECT) as NUM_CONTIN
      FROM OBS_MASTER om
     ) om
WHERE PROJECT = '074190'
GROUP BY PROJECT,
         (CASE WHEN NUM_CONTIN = 0 AND TYPE = 'ASBESTOS' THEN 'CONTIN' ELSE TYPE
          END)

Answer 2

这是另一种选择：

SQL> with
  2  obs_master (project, type, obligation) as
  3    -- sample data
  4    (select 1, 'ASBESTOS', 2500 from dual union all
  5     select 1, 'CONTIN'  , 1500 from dual union all
  6     select 1, 'CM'      ,  500 from dual union all
  7     --
  8     select 2, 'ASBESTOS', 1000 from dual union all
  9     select 2, 'CM'      , 1000 from dual
 10    ),
 11  temp as
 12    -- check whether project has CONTIN type
 13    (select project, min(type) cb_contin
 14     from obs_master
 15     group by project, type
 16     having type = 'CONTIN'
 17    )
 18  select a.project,
 19         -- if type = ASBESTOS and that project doesn't contain CONTIN,
 20         -- replace ASBESTOS with CONTIN
 21         case when a.type = 'ASBESTOS' and
 22                   b.cb_contin <> 'CONTIN'
 23              then 'CONTIN'
 24              else a.type
 25         end type,
 26         sum(a.obligation) obs
 27  from obs_master a left join temp b on a.project = b.project
 28  group by a.project,
 29         case when a.type = 'ASBESTOS' and
 30                   b.cb_contin <> 'CONTIN'
 31              then 'CONTIN'
 32              else a.type
 33         end
 34  order by a.project;

   PROJECT TYPE            OBS
---------- -------- ----------
         1 ASBESTOS       2500
         1 CM              500
         1 CONTIN         1500
         2 ASBESTOS       1000
         2 CM             1000

SQL>

Answer 3

如果您的目标只是更新类型值，那么类似以下语句的方法可能会起作用：

UPDATE OBS_MASTER
SET TYPE='CONTIN'
WHERE TYPE='ASBESTOS' and 
  PROJECT not in 
  (select distinct PROJECT 
   from OBS_MASTER 
   where TYPE='CONTIN')

希望这会有所帮助。

根据条件为每个唯一标识符更新值

3 个答案: