我有2个列表,看起来像:
temp_data:
{
"id": 1,
"name": "test (replaced)",
"code": "test",
"last_update": "2020-01-01",
"online": false,
"data": {
"temperature": [
{
"date": "2019-12-17",
"value": 23.652905748126333
},
...
]}
hum_data:
{
"id": 1,
"name": "test (replaced)",
"code": "test",
"last_update": "2020-01-01",
"online": false,
"data": {
"humidity": [
{
"date": "2019-12-17",
"value": 23.652905748126333
},
...
]}
我需要将2个列表合并为1个而不重复数据。最简单/有效的方法是什么?合并后,我想要这样的东西:
{
"id": 1,
"name": "test",
"code": "test",
"last_update": "2020-01-01",
"online": false,
"data": {
"temperature": [
{
"date": "2019-12-17",
"value": 23.652905748126333
},
...
],
"humidity": [
{
"date": "2019-12-17",
"value": 23.652905748126333
},
...
感谢您的帮助。
答案 0 :(得分:0)
如果未对列表hum_data和temp_data进行排序,请先对它们进行排序,然后将字典成对连接。
# To make comparisons for sorting
compare_function = lambda value : value['id']
# sort arrays before to make later concatenation easier
temp_data.sort(key=compare_function)
hum_data.sort(key=compare_function)
combined_data = temp_data.copy()
# concatenate the dictionries using the update function
for hum_row, combined_row in zip(hum_data, combined_data):
combined_row['data'].update(hum_row['data'])
# combined hum_data and temp_data
combined_data
如果列表已经排序,则只需按字典将字典连接起来。
combined_data = temp_data.copy()
# concatenate the dictionries using the update function
for hum_row, combined_row in zip(hum_data, combined_data):
combined_row['data'].update(hum_row['data'])
# combined hum_data and temp_data
combined_data
使用该代码,我得到了以下结果:
[
{
'id': 1,
'name': 'test (replaced)',
'code': 'test',
'last_update': '2020-01-01',
'online': False,
'data': {
'temperature': [{'date': '2019-12-17', 'value': 1}],
'humidity': [{'date': '2019-12-17', 'value': 1}]}
},
{
'id': 2,
'name': 'test (replaced)',
'code': 'test',
'last_update': '2020-01-01',
'online': False,
'data': {
'temperature': [{'date': '2019-12-17', 'value': 2}],
'humidity': [{'date': '2019-12-17', 'value': 2}]}
}
]