Question

// Write a program that uses a while loop to detect and print multiples of 13 or 17, but not both. Use the exclusive or operator as on page 93. 
// The program should start examining integers at 200, and examine successively larger integers until 16 multiples have been detected. 
// Correct multiples should be printed right aligned in fields that are 9 characters wide, but with only four multiples per line. 
// The total of all correct multiples should be reported after all 16 multiples have been printed.

package Programs5;

public class Program51 {

    public static void main(String[] args) {
        int main = 200, x = 0, y = 13, z = 17;
        while(x < 16) {
            main += 1;
            if(main % y == 0 ^ main % z == 0) {
                x += 1;
                System.out.print(main + " ");
            }
        }
    }

}

当我运行程序时，逻辑起作用并正确打印每个倍数。但是我需要每行打印四个迭代。例如：

x x x x

我很难弄清楚这个。我假设我需要某种形式的循环，从我的小蟒蛇的经验，但我只是失去了这一点。

Answer 1

您忘了将字段对齐为9个字符宽的列（我将使用printf，而当count为4的倍数时，只需添加一个换行符）。我首先将模运算的结果保存在局部变量中。另外，您需要保持运行总计。像

int count = 0, total = 0, start = 200;
for (; count < 16; start++) {
    boolean mod13 = start % 13 == 0, mod17 = start % 17 == 0;
    if (mod13 ^ mod17) {
        if (count > 0) {
            if (count % 4 == 0) {
                System.out.println();
            } else {
                System.out.print(" ");
            }
        }
        total += start;
        System.out.printf("% 9d", start);
        count++;
    }
}
System.out.printf("%nTotal = %d%n", total);

输出

      204       208       234       238
      247       255       260       272
      273       286       289       299
      306       312       323       325
Total = 4331

使用Java-每9个字符宽的行打印四个迭代

1 个答案: