包装对象并通过包装器更改包装的对象

Question

我想包装一些对象以便为它们提供其他属性。但是，当我与在基类上定义的属性进行交互时，原始的未包装对象将发生更改。

我是一个类层次结构，例如：

(json/write-str (lacinia/execute compiled-schema query variables context)) 

如果我有一个程序，那么：

public class SomeBase
{
    public SomeObj Source { get; set; }
    public SomeObj Target { get; set; }

    public SomeBase(SomeObj source, SomeObj target)
    {
        Source = source;
        Target = target;
    }
}

public class SomeDerrived : SomeBase
{
    public SomeDerrived(SomeBase s) : base(s.Source, s.Target) {}
}

public class SomeObj {}

有没有办法做到这一点？

就像SomeBase s = new SomeBase(new SomeObj(), new SomeObj()); SomeDerrived sd = new SomeDerrived(s); WriteLine(s.Source.GetHashCode()); WriteLine(sd.Source.GetHashCode()); //The two hash codes are identical as I'd have expected. sd.Source = new SomeObj(); WriteLine(s.Source.GetHashCode()); //Why does this not have the hash code of `sd`? WriteLine(sd.Source.GetHashCode()); isa SomeDerrived一样，我认为这些属性将是相同的吗？