Question

我有以下数据框

private player

现在，我需要删除行以获得以下输出。

WorldBlocks

我尝试了以下方法。而且它们似乎都不起作用。

df = pd.DataFrame([['1','aa','ccc','rere','thth','my desc 1','','my feature2 1'], ['1','aa','fff','flfl','ipip','my desc 2','',''], ['1','aa','mmm','rprp','','','',''], ['2','aa','ccc','rprp','','','my feature1 1',''], ['2','aa','fff','bubu','thth','my desc 3','',''], ['2','aa','mmm','fafa','rtrt','my desc 4','',''], ['3','aa','ccc','blbl','thth','my desc 5','my feature1 2','my feature2 2'], ['3','aa','fff','arar','amam','my desc 6','',''], ['3','aa','mmm','acac','ryry','my desc 7','',''],['4','bb','coco','rere','','','','my feature2 3'], ['4','bb','inin','mimi','rere','my desc 8','',''], ['4','bb','itit','toto','enen','my desc 9','',''], ['4','bb','spsp','glgl','pepe','my desc 10','',''], ['5','bb','coco','baba','mpmp','my desc 11','my feature1 3',''], ['5','bb','inin','rere','','','',''],['5','bb','itit','toto','hrhr','my desc 12','',''], ['5','bb','spsp','glgl','lolo','my desc 13','','']], columns=['foo', 'bar','name_input','value_input','bulb','desc','feature1', 'feature2'])

非常感谢您的帮助！

Answer 1

`astype(bool)`

在布尔上下文中，空字符串的值为False。使用filter仅获取以feature开头的列。然后使用astype(bool)，然后使用any(axis=1)

df[df.filter(regex='fea').astype(bool).any(1)]

   foo bar name_input value_input  bulb        desc       feature1       feature2
0    1  aa        ccc        rere  thth   my desc 1                 my feature2 1
3    2  aa        ccc        rprp                    my feature1 1               
6    3  aa        ccc        blbl  thth   my desc 5  my feature1 2  my feature2 2
9    4  bb       coco        rere                                   my feature2 3
13   5  bb       coco        baba  mpmp  my desc 11  my feature1 3

为匹配您的结果，我们可以回填desc列

feat = df.filter(regex='feat').astype(bool).any(1)
desc = df.desc.where(df.desc.astype(bool)).bfill()
df.assign(desc=desc)[feat]

   foo bar name_input value_input  bulb        desc       feature1       feature2
0    1  aa        ccc        rere  thth   my desc 1                 my feature2 1
3    2  aa        ccc        rprp         my desc 3  my feature1 1               
6    3  aa        ccc        blbl  thth   my desc 5  my feature1 2  my feature2 2
9    4  bb       coco        rere         my desc 8                 my feature2 3
13   5  bb       coco        baba  mpmp  my desc 11  my feature1 3

Answer 2

另一种方法是将空白字符串更改为真实的NaN值，然后将how参数传递给dropna并使用all作为值

import numpy as np
df.replace('',np.nan).dropna(subset=['feature1','feature2'],how='all').fillna('')


   foo bar name_input value_input  bulb        desc       feature1  feature2
0    1  aa        ccc        rere  thth   my desc 1                 my feature2 1
3    2  aa        ccc        rprp                    my feature1 1   
6    3  aa        ccc        blbl  thth   my desc 5  my feature1 2  my feature2 2
9    4  bb       coco        rere                                   my feature2 3 
13   5  bb       coco        baba  mpmp  my desc 11  my feature1 3

如何根据条件删除大熊猫中的行？

2 个答案:

`astype(bool)`