如何将长字符串压缩成文件并检索它?

时间:2011-05-13 21:06:26

标签: java string file zip

我正在尝试将长字符串压缩成文件并检索它。

以下代码不起作用。它检索的是胡言乱语。

public static void main(String args[]) {

    try {

        // Creating base for data
        StringBuilder sbb = new StringBuilder();
        for (int i=0;i<1000;i++)
            sbb.append("ùertyty!|").append(Integer.toString(i));

        File FileAll = new File(".\\All.data");
        FileAll.createNewFile();

        // Zipping into file
        DeflaterOutputStream g = new DeflaterOutputStream(
                new FileOutputStream(FileAll));

        OutputStreamWriter osw = new OutputStreamWriter(g);

        String base = sbb.toString();
        osw.write(base);
        osw.close();

        FileInputStream ALL_FIS = new FileInputStream(FileAll);

        // Re-reading from file
        DeflaterInputStream dis = new DeflaterInputStream(ALL_FIS);
        InputStreamReader isr = new InputStreamReader(dis);

        StringBuilder sb = new StringBuilder();
        char[] c = new char[1000];

        int count = isr.read(c);

        while ( count != -1 ) {
            sb.append(c, 0, count);
            count = isr.read(c);
        }

        isr.close();

        String retr = sb.toString();
        System.out.println("Are equal: " + retr.equals(base));
        System.out.println("Base: " + base);
        System.out.println("Retr: " + retr);

    } catch (IOException e) {

        System.err.println(e.toString());

    }

}

我做错了什么?

P.S。:似乎DeflaterInputStream不能正常工作并按原样返回文件内容。

1 个答案:

答案 0 :(得分:5)

您需要使用InflaterInputStream(解压缩)而不是DeflaterInputStream

http://download.oracle.com/javase/1.5.0/docs/api/java/util/zip/InflaterInputStream.html