如何在Android中挂断电话?

时间:2009-03-01 07:37:55

标签: android telephony telephonymanager

我正在开发一个应用程序,其中我们需要的一件事就是控制传出呼叫,至少能够从我们的应用程序中阻止它。

我尝试使用现有活动中的Intent.ACTION_CALL

Intent callIntent = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + phoneNumber)); 
startActivity(callIntent); 

但是通过API似乎不允许停止呼叫。

你能建议一些解决方法吗?

例如:在通话期间启用飞机模式?只是一个例子;这个黑客对我不起作用。

8 个答案:

答案 0 :(得分:31)

已经提到在BroadcastReceiver中捕获拨出电话,如果您想在拨号前结束通话,这绝对是最好的方式。

然而,一旦拨号或通话,该技术就不再适用。我到目前为止挂断的唯一方法是通过Java Reflection这样做。由于它不是公共API的一部分,因此您应该小心使用它,而不是依赖它。对Android内部组成的任何更改都将有效地破坏您的应用程序。

Prasanta Paul's blog demonstrates如何实现,我在下面进行了总结。

获取ITelephony对象:

TelephonyManager tm = (TelephonyManager) context
        .getSystemService(Context.TELEPHONY_SERVICE);
try {
    // Java reflection to gain access to TelephonyManager's
    // ITelephony getter
    Log.v(TAG, "Get getTeleService...");
    Class c = Class.forName(tm.getClass().getName());
    Method m = c.getDeclaredMethod("getITelephony");
    m.setAccessible(true);
    com.android.internal.telephony.ITelephony telephonyService =
            (ITelephony) m.invoke(tm);
} catch (Exception e) {
    e.printStackTrace();
    Log.e(TAG,
            "FATAL ERROR: could not connect to telephony subsystem");
    Log.e(TAG, "Exception object: " + e);
}

结束通话:

telephonyService.endCall();

答案 1 :(得分:26)

试试这个:

(我使用了Reflection to access advanced telephony features并修改了某些内容)

// required permission <uses-permission android:name="android.permission.CALL_PHONE"/>

try {
    //String serviceManagerName = "android.os.IServiceManager";
    String serviceManagerName = "android.os.ServiceManager";
    String serviceManagerNativeName = "android.os.ServiceManagerNative";
    String telephonyName = "com.android.internal.telephony.ITelephony";

    Class telephonyClass;
    Class telephonyStubClass;
    Class serviceManagerClass;
    Class serviceManagerStubClass;
    Class serviceManagerNativeClass;
    Class serviceManagerNativeStubClass;

    Method telephonyCall;
    Method telephonyEndCall;
    Method telephonyAnswerCall;
    Method getDefault;

    Method[] temps;
    Constructor[] serviceManagerConstructor;

    // Method getService;
    Object telephonyObject;
    Object serviceManagerObject;

    telephonyClass = Class.forName(telephonyName);
    telephonyStubClass = telephonyClass.getClasses()[0];
    serviceManagerClass = Class.forName(serviceManagerName);
    serviceManagerNativeClass = Class.forName(serviceManagerNativeName);

    Method getService = // getDefaults[29];
    serviceManagerClass.getMethod("getService", String.class);

    Method tempInterfaceMethod = serviceManagerNativeClass.getMethod(
                "asInterface", IBinder.class);

    Binder tmpBinder = new Binder();
    tmpBinder.attachInterface(null, "fake");

    serviceManagerObject = tempInterfaceMethod.invoke(null, tmpBinder);
    IBinder retbinder = (IBinder) getService.invoke(serviceManagerObject, "phone");
    Method serviceMethod = telephonyStubClass.getMethod("asInterface", IBinder.class);

    telephonyObject = serviceMethod.invoke(null, retbinder);
    //telephonyCall = telephonyClass.getMethod("call", String.class);
    telephonyEndCall = telephonyClass.getMethod("endCall");
    //telephonyAnswerCall = telephonyClass.getMethod("answerRingingCall");

    telephonyEndCall.invoke(telephonyObject);

} catch (Exception e) {
    e.printStackTrace();
    Log.error(DialerActivity.this,
                "FATAL ERROR: could not connect to telephony subsystem");
    Log.error(DialerActivity.this, "Exception object: " + e);
}

答案 2 :(得分:21)

  1. 创建优先级为0的BroadcastReceiver
  2. 在BC中截取其ACTION_NEW_OUTGOING_CALL方法
  3. 中的onReceive意图
  4. 使用相同的方法调用setResultData(null)
  5. 这会阻止呼叫发起(只要你的接收者是最后一个处理我认为的意图)

答案 3 :(得分:5)

您可以尝试启用然后禁用飞行模式:

android.provider.Settings.System.putInt(getContentResolver(),
        android.provider.Settings.System.AIRPLANE_MODE_ON, 1);

Intent intent = new Intent(Intent.ACTION_AIRPLANE_MODE_CHANGED);
intent.putExtra("state", 1);
sendBroadcast(new Intent("android.intent.action.AIRPLANE_MODE"));
sendBroadcast(intent);
android.provider.Settings.System.putInt(getContentResolver(),
        android.provider.Settings.System.AIRPLANE_MODE_ON, 0);

intent.putExtra("state", 0);
sendBroadcast(new Intent("android.intent.action.AIRPLANE_MODE"));
sendBroadcast(intent);

答案 4 :(得分:4)

对于Ilana:

public class ilanasReceiver extends BroadcastReceiver {
    public void onReceive(Context context, Intent intent) {
        if (intent.getAction().equals(Intent.ACTION_NEW_OUTGOING_CALL)) {
            if (getResultData()!=null) {
                String number = "123456";
                setResultData(number);
            }
        }
    }
}

另外在Manifest中放入包部分:

<uses-permission android:name="android.permission.PROCESS_OUTGOING_CALLS" />

就是这样。

答案 5 :(得分:4)

这是最新的代码,它也适用于Android P,因为它具有正式的API(here):

在清单中,添加以下内容:

hts

在代码中,使用此:

Java:

<uses-permission android:name="android.permission.ANSWER_PHONE_CALLS"/>

或在科特林:

@SuppressLint("PrivateApi")
public static boolean endCall(Context context) {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
        final TelecomManager telecomManager = (TelecomManager) context.getSystemService(Context.TELECOM_SERVICE);
        if (telecomManager != null && ContextCompat.checkSelfPermission(context, Manifest.permission.ANSWER_PHONE_CALLS) == PackageManager.PERMISSION_GRANTED) {
            telecomManager.endCall();
            return true;
        }
        return false;
    }
    //use unofficial API for older Android versions, as written here: https://stackoverflow.com/a/8380418/878126
    try {
        final Class<?> telephonyClass = Class.forName("com.android.internal.telephony.ITelephony");
        final Class<?> telephonyStubClass = telephonyClass.getClasses()[0];
        final Class<?> serviceManagerClass = Class.forName("android.os.ServiceManager");
        final Class<?> serviceManagerNativeClass = Class.forName("android.os.ServiceManagerNative");
        final Method getService = serviceManagerClass.getMethod("getService", String.class);
        final Method tempInterfaceMethod = serviceManagerNativeClass.getMethod("asInterface", IBinder.class);
        final Binder tmpBinder = new Binder();
        tmpBinder.attachInterface(null, "fake");
        final Object serviceManagerObject = tempInterfaceMethod.invoke(null, tmpBinder);
        final IBinder retbinder = (IBinder) getService.invoke(serviceManagerObject, "phone");
        final Method serviceMethod = telephonyStubClass.getMethod("asInterface", IBinder.class);
        final Object telephonyObject = serviceMethod.invoke(null, retbinder);
        final Method telephonyEndCall = telephonyClass.getMethod("endCall");
        telephonyEndCall.invoke(telephonyObject);
        return true;
    } catch (Exception e) {
        e.printStackTrace();
        LogManager.e(e);
    }
    return false;
}

答案 6 :(得分:3)

考虑到可能出现的恶作剧,如果允许,我会感到惊讶。

这个帖子断然说the API cannot end a call。其他have tried

答案 7 :(得分:0)

根据ACTION_NEW_OUTGOING_CALL

的文件

意图将具有以下额外值:

EXTRA_PHONE_NUMBER - 最初打算拨打的电话号码。

广播完成后,resultData将用作要调用的实际号码。如果为null,则不会进行任何调用。