Question

有3个交易，如下所示，我只想求和等于或大于3500的交易编号：

transaction no.   total
0001              1,000 
0001              2,000 
0001              3,000 
0001              4,000 

0002              2,000 
0002              3,000 

0003              1,000 
0003              1,000 
0003              1,000

这是我期望的结果：

transaction no.   total
0001              10,000 
0002              5,000

当然，交易号。 0003低于3500，因此不会显示。

Answer 1

将@Query(value = "SELECT * FROM table WHERE column ->> 'Id'=?1", nativeQuery = true) public Entity fertchById(String id);与group by一起使用

Having Clause

Answer 2

您只需要使用如下的hading子句：

SELECT transactionNo, SUM(total) AS total
FROM myTable
GROUP BY transactionNo
HAVING SUM(total) > 3500

Answer 3

将HAVING子句添加到SQL，因为无法使用WHERE关键字与聚合函数一起使用。

SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);


SELECT transactionNo, SUM(total) AS total
FROM table_name
GROUP BY transactionNo
HAVING SUM(total) > 3500

Answer 4

您可以使用以下代码：

SELECT DISTINCT     transactionNo,
   runningtotal
FROM   (
       SELECT myTable1.transactionNo,
              myTable1.total,
              SUM(myTable2.total) AS runningtotal
       FROM   myTable myTable1
              INNER JOIN myTable myTable2
                   ON  myTable1.transactionNo = myTable2.transactionNo
       GROUP BY
              myTable1.transactionNo,
              myTable1.total
   )            result
WHERE  runningtotal > 3500

或者您可以使用窗口功能和 CTE

;WITH ResultTable AS (
      SELECT DISTINCT transactionNo,
             SUM(total) OVER(PARTITION BY transactionNo) AS total
      FROM   myTable
  )

SELECT *
FROM   ResultTable
WHERE  ResultTable.total > 3500

仅当一个值等于或大于3500时才求和吗？

4 个答案: