我有出价表,每个出价都有金额和AuctionID。
我希望SUM / SELECT每个AuctionID的所有最高出价..
示例:
结果:
SELECT AuctionID,Amount, Highest FROM Bids Where Burned=0 ORDER BY Amount DESC
AuctionID Amount Highest
1 44.4400 0
3 43.7800 0
2 42.3300 0
1 22.2200 0
4 21.2700 0
1 21.2600 0
4 21.2500 0
2 21.2400 0
1 12.6600 0
4 12.5200 0
应返回 44.44 , 43.78 , 42.33 , 21.27 。
'最高'是一个我认为可能有用的旗帜,它仍然毫无用处。 我想看看是否有一种方法可以不使用Flag。
答案 0 :(得分:4)
一个简单的group by子句可以解决这个问题:
select AuctionID, MAX(Amount)
from table
group by AuctionID
答案 1 :(得分:4)
SELECT AuctionId, MAX(Amount) FROM TableName GROUP BY AuctionID
答案 2 :(得分:1)
获得所有最高出价:
Select auctionid, max(amount) from auctions group by auctionid
获取最高出价的总和:
select sum(v1.max_amount) from
(Select auctionid, max(amount) max_amount from auctions group by auctionid
) as v1