我最近用简单的算法制作了一个机器人。该机器人应该在某个频道上欢迎您,然后您必须告诉他您的名字级别(在特定游戏中)和您的团队(team1 team2或team3)。当您这样做时,他应该以您的昵称和级别为您命名,并在您的团队之后设置您的不和谐角色,最后,在他这样做之后,他要您在pm上获取您的个人资料的屏幕快照,然后将其发送到另一个频道(这不是重要的部分)。
命名部分和屏幕截图功能正常运行,并且按预期运行,尽管出于某些未知原因,setRole函数看似随机运行。它有时赋予成员正确的角色,有时却没有。这是我的算法:
if (message.channel.id == welcomeid){
var words = message.content.split(' ');
var name = words[0];
var number = words[1];
var team = words[2];
if (typeof words[0] === "undefined" || typeof words[1] === "undefined" || typeof words[2] === "undefined"){
message.reply("error checker")
return;
}
team = team.toLowerCase();
if (name.includes('team1') == 1 || name.includes('team2') == 1 || name.includes('team3') == 1 || name.includes('team4') == 1 ){
message.reply("Another error");
return;
}
else if (name.length < 3){
message.reply("error for name length");
return;
}
else if (isNaN(number)){
message.reply("error for checking if level is a number");
return;
}
else if (number > 40 || number < 1 ) {
message.reply("error for checking if level is above one and below 40");
return;
}
else {
if (team.includes("team1")){ //those 4 ifs are the problematic part
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team1id)
.then(console.log)
.catch(console.error);
screenShot();
}
else if (team.includes("team2")){
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team2id)
.then(console.log)
.catch(console.error);
screenShot();
}
else if (team.includes("team3")){
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team3id)
.then(console.log)
.catch(console.error);
screenShot();
}
else if (team.includes("team4")){
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team4id)
.then(console.log)
.catch(console.error);
screenShot();
}
else {
message.reply("team error");
return;
}
}
}
当然,我不需要机器人在需要的时候就扮演角色,并且我看不到任何与“ addrole”功能相抵触的代码。
答案 0 :(得分:1)
您的代码中没有可见的错误,我唯一要摆脱的是不必要的else块。因为如果任何一个参数输入不正确,则将函数保留为return
。检查您的漫游器角色是否高于所有参与者的角色。如果没有,他将无法更改昵称或放弃这个角色。
if (message.channel.id == welcomeid){
var words = message.content.split(' ');
var name = words[0];
var number = words[1];
var team = words[2];
if (typeof words[0] === "undefined" || typeof words[1] === "undefined" || typeof words[2] === "undefined"){
return message.reply("error checker")
}
team = team.toLowerCase();
if (name.includes('team1') == 1 || name.includes('team2') == 1 || name.includes('team3') == 1 || name.includes('team4') == 1 ){
message.reply("Another error");
return;
} else if (name.length < 3){
message.reply("error for name length");
return;
} else if (isNaN(number)){
message.reply("error for checking if level is a number");
return;
} else if (number > 40 || number < 1 ) {
message.reply("error for checking if level is above one and below 40");
return;
}
if (team.includes("team1")){
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team1id)
.then(console.log)
.catch(console.error);
screenShot();
} else if (team.includes("team2")){
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team2id)
.then(console.log)
.catch(console.error);
screenShot();
} else if (team.includes("team3")){
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team3id)
.then(console.log)
.catch(console.error);
screenShot();
} else if (team.includes("team4")){
message.member.setNickname(name+" | "+number)
.then(console.log)
.catch(console.error);
message.member.addRole(team4id)
.then(console.log)
.catch(console.error);
screenShot();
} else {
message.reply("team error");
return;
}
}