Question

我正在过滤数据集，该块工作正常：

    dwell <- rail %>% 
  filter_(Measure == "Average Terminal Dwell Time (Excluding Cars on Run Through Trains) (Hours)",
         Variable == "System") %>% 
  gather(Date, Hrs, -("railroad":"Sub-Variable"))

但是我想运行以下代码，在变量下添加第二个选项：

dwell <- rail %>% 
  filter_(Measure == "Average Terminal Dwell Time (Excluding Cars on Run Through Trains) (Hours)",
         Variable == "System" & "System (U.S.)") %>% 
  gather(Date, Hrs, -("railroad":"Sub-Variable"))

但是，当我这样做时，我得到了以下错误：“只能对数字，逻辑或复杂类型进行操作。”我尝试将＆换为|那也不起作用。一旦有人告诉我，我觉得这将是一个简单的转换。谢谢！

Answer 1

尝试将Variable == "System" & "System (U.S.)"的{{1}}更改为Variable == "System" | Variable == "System (U.S.)"。应该可以。

Answer 2

如果我们尝试对多个元素（例如> 1）进行固定匹配，则可以将%in%与Variable一起使用。对于%in%，我们可以将任意数量的元素作为{{ 1}}

vector

如果可以与library(dplyr) library(tidyr) rail %>% filter_(Measure == "Average Terminal Dwell Time (Excluding Cars on Run Through Trains) (Hours)", Variable %in% c("System", "System (U.S.)")) %>% gather(Date, Hrs, -("railroad":"Sub-Variable"))匹配，则可能会更容易

regex

在OP的代码rail %>% filter_(Measure == "Average Terminal Dwell Time (Excluding Cars on Run Through Trains) (Hours)", startsWith(Variable, "System")) %>% gather(Date, Hrs, -("railroad":"Sub-Variable"))中，Variable == "System" & "System (U.S.)"部分未进行评估，因为我们需要两次指定“变量”，但这仍然不正确，因为该列不能包含两个元素相同的位置

根据两个非数字值在dplyr中进行过滤

2 个答案: