Question

如何获取table1中不存在的table2记录（已过滤日期）

SELECT e.event_id, e.start_time, te.* 
FROM table1 te, table2_tmp e 
WHERE te.book_id = 45
 AND (DATE(STR_TO_DATE(e.start_time,"%Y%m%d%H%i%s")) BETWEEN DATE(DATE_SUB(NOW(),INTERVAL 1 YEAR)) AND CURRENT_DATE)

表1

ID      event_id  start_time      book_id
10000   1_1005    20191222135100  45  <-- date Filtered & Doesn't exists in t1
10001   1_1006    20200123139100  45
10002   1_1007    20200124145100  45
10003   1_1010    20200125135100  45
10004   1_1015    20200325135100  46

table2

ID      bk_event_id  
11111   1_1006   
11112   1_1007         
11113   1_1015
11113   1_1016

预期结果

ID      event_id  
10000   1_1016

Answer 1

您可以使用外部联接：请参见此示例

这将选择PLAYERS表中没有球员的所有球队。

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

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      <li><a href="#" class="feat-btn box-two" id="design">
      <span>button 2</span>
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      <li><a href="#" class="feat-btn box-three" id="film">
      <span>button 3</span>
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      <p id="marketing-blurp" class="hide-blurp">Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris</p>
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example

Answer 2

您可以使用NOT IN，可以将数据从一个表中排除到另一个表中。我认为您在2个表中定义的数据和预期结果不正确。

您可以尝试通过添加条件来查询此查询。

SELECT t2.* from table2 t2 
where bk_event_id NOT IN (SELECT t1.event_id from table1 t1)

从一个表中选择其他表中不存在的记录

2 个答案: