我不擅长Regex，但是我被要求编辑一个已有字符来解释某个字符（，）。
原文：// doFilter() in KerberosAuthFilter
//the KerberosAuthFilter class is the same as the custom SpnegoAuthenticationProcessingFilter, //except for the end of the doFilter () method
@Override
public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException {
HttpServletRequest request = (HttpServletRequest) req;
HttpServletResponse response = (HttpServletResponse) res;
if (skipIfAlreadyAuthenticated) {
Authentication existingAuth = SecurityContextHolder.getContext().getAuthentication();
if (existingAuth != null && existingAuth.isAuthenticated()
&& (existingAuth instanceof AnonymousAuthenticationToken) == false) {
chain.doFilter(request, response);
return;
}
}
String header = request.getHeader("Authorization");
if (header != null && (header.startsWith("Negotiate ") || header.startsWith("Kerberos "))) {
if (logger.isDebugEnabled()) {
logger.debug("Received Negotiate Header for request " + request.getRequestURL() + ": " + header);
}
byte[] base64Token = header.substring(header.indexOf(" ") + 1).getBytes("UTF-8");
byte[] kerberosTicket = Base64.decode(base64Token);
KerberosServiceRequestToken authenticationRequest = new KerberosServiceRequestToken(kerberosTicket);
authenticationRequest.setDetails(authenticationDetailsSource.buildDetails(request));
Authentication authentication;
try {
authentication = authenticationManager.authenticate(authenticationRequest);
} catch (AuthenticationException e) {
logger.warn("Negotiate Header was invalid: " + header, e);
SecurityContextHolder.clearContext();
if (failureHandler != null) {
failureHandler.onAuthenticationFailure(request, response, e);
} else {
response.setStatus(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
response.flushBuffer();
}
return;
}
sessionStrategy.onAuthentication(authentication, request, response);
SecurityContextHolder.getContext().setAuthentication(authentication);
if (successHandler != null) {
successHandler.onAuthenticationSuccess(request, response, authentication);
}
chain.doFilter(request, response);
} else {
response.sendRedirect("/login.html");
System.out.println("redirect");
return;
}
}
我的阅读方式：任何不在＆＃32和＆＃126之间的字符。逗号是＆＃44
我的新正则表达式：
[^ -~]我的阅读方式：任何字符不在＆＃32和＆＃43之间，并且任何字符不在＆＃45和＆＃126
之间但是新的正则表达式似乎不适用于我的情况。
答案 0 :(得分：0)
您的新正则表达式实际上是在+后面的空格中寻找一个字符，然后是&，然后是-到~以外的字符。相反，您应该将两个范围合并为一个字符类：
[^ -+--~]
https://github.com/moby/moby/issues/26817
您还可以使用替换来允许,：
,|[^ -~]