Question

我有这个

list = ['John', 21, 'Smith', 30, 'James', 25]

我想将它们分为以下

name = ['John', 'Smith', 'James']
age = [21, 30, 25]

Answer 1

您可以执行此操作。请勿使用keywords和built-in作为变量名。

使用切片

Understanding Slicing Notation

lst=['John', 21, 'Smith', 30, 'James', 25]
name=lst[::2] 
age=lst[1::2]

或者您可以使用 列表理解

List Comprehension Reference

name=[val for idx,val in enumerate(lst) if idx%2==0]
age=[val for idx,val in enumerate(lst) if idx%2==1]

Answer 2

遍历列表。如果可以将元素的索引除以2而没有余数，则将元素添加到列表名称。如果将索引除以2时还有余数，则将元素追加到列表年龄。列表索引从0开始。枚举使元素的索引在迭代列表时可用。用除法运算符检查除数的余数。

lst = ['John', 21, 'Smith', 30, 'James', 25]

#Create list name to store the names
name = []
#Create list age to store the age
age = []

# use for loop to access every element of lst
# using enumerate(lst) let's us access the index of every element in the variable index see reference [0]
# The indexes of the list elements are as following:
# John: 0, 21: 1, Smith: 2, 30: 3, James: 4, 25: 5
for index,element in enumerate(lst):
    #Check if the index of an element can be divided by 2 without a remainder
    #This is true for the elements John, Smith and James:
    #0 / 2 = 0 remainder 0
    #2 / 2 = 1 remainder 0
    #4 / 2 = 2 remainder 0
    if index % 2 == 0:
       name.append(element)
    # If the division of the index of an element yields remainder, add the element to the list age
    # This is true for the elements 21, 30 and 25:
    # 1 / 2 = 0 remainder 1
    # 3 / 2 = 1 remainder 1
    # 5 / 2 = 2 remainder 1
    else:
        age.append(element)

print(name)
print(age)

参考：

[0] https://docs.python.org/3/library/functions.html#enumerate
[1] https://docs.python.org/3.3/reference/expressions.html#binary-arithmetic-operations。

Answer 3

一种不太方便的方法是使用列表索引：

<Router>
  <Switch>
    <Route exact path="/series" component={SeriesLibrary} />
    <Route exact path="/series/:series_id" component={EpisodeLibrary} />
    <Route
      path="/series/:series_id/episode/:episode_id"
      component={Episode}
    />
  </Switch>
</Router>

将整数和字符串拆分为其他列表

3 个答案: