Question

我希望将多行合并为具有匹配ID的一行。我正在使用Teradata SQL。示例：

  SELECT
  id_nbr AS ID,
  contact_type AS contype,
  contact_first_name AS firstName,
  contact_last_name AS lastName,
  contact_phone_number AS phoneNumber,
  contact_address AS address,
  contact_email AS email
  FROM database.account_info
  WHERE (contact_type = 'AAA' OR contact_type = 'BBB' OR contact_type = 'CCC');

结果：

ID          contype     firstName     lastName    phoneNumber     address        email
111111111   AAA         bob           smith       (999)999-9999   1 Main St      null
111111111   BBB         bob           smith       (888)888-8888   1 random rd    bob@random.com
111111111   CCC         bob           smith       null            null           bob@anotherrandom.com

我想要什么：

ID          contypeAAA     firstNameAAA     lastNameAAA    phoneNumberAAA     addressAAA      emailAAA   contypeBBB  firstNameBBB     lastNameBBB    phoneNumberBBB     addressBBB      emailBBB  contypeCCC     firstNameCCC     lastNameCCC    phoneNumberCCC     addressCCC      emailCCC
111111111   AAA            bob              smith          (999)999-9999      1 Main St       null ......etc

这甚至可能吗？这将极大地帮助我..！预先感谢！

编辑此ID的子类型并不总是具有全部3个子类型。这使它更加棘手。例如，ID：99999999只能具有子类型：“ AAA”，“ BBB”，但应为所有“ CCC”值返回空值，因为它不存在。

Answer 1

我相信这会起作用（我在Oracle 11g而不是Teradata上进行了测试）：

SELECT *
  FROM (SELECT id_nbr AS ID,
               contact_type AS contype,
               contact_first_name AS firstName,
               contact_last_name AS lastName,
               contact_phone_number AS phoneNumber,
               contact_address AS address,
               contact_email AS email
          FROM database.account_info
         WHERE contact_type in ('AAA', 'BBB', 'CCC')
        )
 PIVOT (max(firstName) AS firstName,
        max(lastName) AS lastName,
        max(phoneNumber) AS phone,
        max(email) AS email,
        max(address) AS address
   FOR contype IN ('AAA', 'BBB', 'CCC')
        )

最后一行可能需要别名，其中之一：

        ) AS derived_pivot
        ) derived_pivot

将多行（具有相同ID）合并为一个？

1 个答案: