我有两个表exam_table和emp_table,在这里我想使用左外部联接将两个表联接起来,我想使用右表中的exam_completed_date列创建一个名为new_column的新列。
invoke-command comp1,comp2,comp3 { sleep 5; "done $env:computername" }
我需要这样的输出
select id, exam_completed_date from exam_table;
id exam_completed_date
0 12-01-2019
1 12-12-2019
select id, week_end_date from emp_table where id=0;
id week_end_date
0 11-29-2019
0 11-30-2019
0 12-31-2019
0 12-01-2019
0 12-02-2019
0 12-03-2019
0 12-04-2019
select id, week_end_date, exam_completed_date
from emp_table emp left outer join
exam_table exam
on (exam.id=emp.id and exam.exam_completed_date=emp.week_end_date)
where id=0
id week_end_date exam_completed_date
0 11-29-2019
0 11-30-2019
0 12-31-2019
0 12-01-2019 12-01-2019
0 12-02-2019
0 12-03-2019
0 12-04-2019
答案 0 :(得分:1)
我认为您需要累积最大窗口函数:
select id, week_end_date, exam_completed_date,
max(exam_completed_date) over (partition by id order by week_end_date) as newcolumn
from emp_table emp left outer join
exam_table exam
on exam.id=emp.id and
exam.exam_completed_date = emp.week_end_date
where id = 0;