Question

我想知道当trt = C时如何从一行中所有其他列中删除所有数据。我对一种适用于许多专栏的解决方案感兴趣！

    proc VGAPlaneSelect
        push ax
        push dx
        push cx
        mov al, 02h
        mov dx, 03C4h
        out dx, al
        VGAPlaneSelect_start:
        mov ax, 1
        mov cl, [VGAPlane]
        shl ax, cl
        cmp [VGAPlane], 4
        jne VGAPlaneSelect_end
            mov [VGAPlane], 0
            jmp VGAPlaneSelect_start
        VGAPlaneSelect_end:
        mov dx, 03C5h
        out dx, al
        pop cx
        pop dx
        pop ax
        ret
    endp VGAPlaneSelect

类似...

A <- sample(1:100,9)
B <- sample(1:100,9)
trt <- rep(c("A", "B", "C"),3) 

df <- data.frame(trt, A, B)
df

    trt A  B
1   A  32 43
2   B  29 79
3   C  94 95
4   A 100 24
5   B  63 38
6   C  80 92
7   A  22 98
8   B  61 56
9   C  69 81


to look like this:
       trt A  B
    1   A 90  50
    2   B 84 100
    3   C NA  NA
    4   A 42  17
    5   B 61  43
    6   C NA  NA
    7   A 78  84
    8   B 27  36
    9   C NA  NA

Answer 1

我们可以使用CREATE TABLE dbo.YourTable (StartDate datetime, EndDate datetime); INSERT INTO dbo.YourTable (StartDate, EndDate) VALUES('2020-01-10T13:00:00.347','2020-01-12T02:00:00.347'), ('2020-01-14T17:24:41.243','2020-01-19T09:17:12.997'); GO WITH N AS( SELECT N FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL))N(N)), Tally AS( SELECT TOP(SELECT MAX(DATEDIFF(DAY, StartDate, EndDate)+1) FROM dbo.YourTable) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1 AS I FROM N N1, N N2, N N3), --1000 days enough? Dates AS( SELECT DATEADD(DAY, T.I,CONVERT(date,YT.StartDate)) AS [Date], CASE WHEN T.I = 0 THEN YT.StartDate ELSE DATEADD(DAY, T.I,CONVERT(date,YT.StartDate)) END AS StartingDateTime, CASE WHEN LEAD(T.I) OVER (PARTITION BY YT.StartDate ORDER BY T.I) IS NULL THEN YT.EndDate ELSE DATEADD(DAY, T.I+1,CONVERT(date,YT.StartDate)) END AS EndingDateTime FROM Tally T JOIN dbo.YourTable YT ON T.I <= DATEDIFF(DAY, YT.StartDate, YT.EndDate)) SELECT D.[Date], (DATEDIFF(SECOND,D.StartingDateTime,D.EndingDateTime) * 1.0) / 60 / 60 AS [Hours] FROM Dates D; GO DROP TABLE dbo.YourTable;选择要更改的行和列，即

给出，

df[df$trt == 'C', -1] <- NA

您也可以使用它来选择特定的列，

  trt  A  B
1   A 87 56
2   B 53 18
3   C NA NA
4   A  8  1
5   B 79 38
6   C NA NA
7   A 48 36
8   B 55 22
9   C NA NA

给出，

df[df$trt == 'C', -c(1, 3)] <- NA

Answer 2

这是功能为<?xml version="1.0" encoding="UTF-8"?> <configuration> <system.webServer> <handlers> <add name="httpPlatformHandler" path="*" verb="*" modules="httpPlatformHandler" resourceType="Unspecified"/> </handlers> <httpPlatform processPath="%JAVA_HOME%\bin\java.exe" arguments="-Djava.net.preferIPv4Stack=true -Dserver.port=%HTTP_PLATFORM_PORT% -jar "%HOME%\site\wwwroot\app.jar""> </httpPlatform> </system.webServer> </configuration>的解决方案。

is.na<-

Answer 3

    for (i in 1:nrow(df)) {
      if (df$trt[i] == "C") {
        df[i, ] <- NA
        df$trt[i] <- "C"
      }
    }

强悍，但有效！

根据数据框中某列的条件，删除同一行其他列中的数据

3 个答案: