Question

我想在满足特定条件时增加一个数字，而在其他部分，我想减少该数字，但这应该在指定的限制之内。条件就像有一个整天的时间戳记，间隔15分钟，因此24小时总共有96个区块。现在，当时间在早上6点至晚上7点之间时，该数字应增加，但应达到一个特定的限制；当时间在晚上7点至第二天早上6点之间时，该数量应减少。我的代码是：

import pandas as pd
import datetime
timeStamp = pd.date_range(start='1/1/2020' , end = '1/1/2020', freq = '15min')
num = 0
numLowerLimit = 0
numHigherLimit = 1
chargeTime = 6
dischargeTime = 19
for t in timeStamp:
   if chargeTime <= t.hour < dischargeTime:
        if numLowerLimit <= num <= numHigherLimit:
            num = num + 0.23
            print(num)
        else:
            num = 1
            print(num)
    else:
        if numLowerLimit <= num <= numHigherLimit:
            num = num - 0.23
            print(num)
        else:
            num = 0
            print(num)

错误：

ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

预期输出：

2020-01-01 06:00:00' - 0.23
2020-01-01 06:15:00' - 0.46
2020-01-01 06:30:00' - 0.69
2020-01-01 06:45:00' - 0.92
2020-01-01 07:00:00' -  1
2020-01-01 07:15:00' -  1
2020-01-01 07:30:00' -  1
.
.
.
2020-01-01 19:00:00' -  1
2020-01-01 19:15:00' -  0.77
2020-01-01 19:30:00' -  0.54
2020-01-01 19:45:00' -  0.31
2020-01-01 20:00:00' -  0.54
2020-01-01 20:15:00' -  0.31
2020-01-01 20:30:00' -  0.08
2020-01-01 20:45:00' -  0
2020-01-01 20:00:00' -  0

Answer 1

尝试一下：

import pandas as pd
import datetime
timeStamp = pd.date_range(start='1/1/2020 06:00:00' , end = '1/1/2020 23:59:00', freq = '15min')
num = 0
numLowerLimit = 0
numHigherLimit = 1
chargeTime = 6
dischargeTime = 19
for t in timeStamp:    
    num = min([num + 0.23, 1]) if chargeTime <= t.hour < dischargeTime else max([num - 0.23, 0])
    print(f'{t} {num:.2f}')

如何在python中增加或减少数字时设置限制？

1 个答案: