Question

我在打字稿中有这个对象数组

[
  {target_col: "`qsze`", operation: "", isNew: false, operationNotCompiled: "", index: 25},
  {target_col: "`qsf`", operation: "", isNew: false, operationNotCompiled: "", index: 26},
  {target_col: "`amiu`", operation: "'jnhghghgh'", isNew: true, operationNotCompiled: "'jnhghghgh'",…},
  {target_col: "`amiu`", operation: "", isNew: false, operationNotCompiled: "", index: 27}
]

我想删除重复的元素。

我想如果没有重复的元素，则返回该对象。否则，如果有重复的元素，则删除具有operationNotCompiled=""的元素。

如果有重复的元素并且两个元素都有operationNotCompiled=""，则删除一个。

2个元素重复===== >>>> 2个元素具有相同的属性target_col。像这样2。

{target_col: "`amiu`", operation: "'jnhghghgh'", isNew: true, operationNotCompiled: "'jnhghghgh'",…},
{target_col: "`amiu`", operation: "", isNew: false, operationNotCompiled: "", index: 27}

Answer 1

欢迎oumaima！

这里是一个示例：

const arr = [
  {target_col: "`qsze`", operation: "", isNew: false, operationNotCompiled: "", index: 25},
  {target_col: "`qsf`", operation: "", isNew: false, operationNotCompiled: "", index: 26},
  {target_col: "`amiu`", operation: "'jnhghghgh'", isNew: true, operationNotCompiled: "'jnhghghgh'"},
  {target_col: "`amiu`", operation: "", isNew: false, operationNotCompiled: "", index: 27}
]

function checkDuplicates(arr) {
  keys = []
  keysDuplicates = [] 
  arr.map(item => {
    if (keys.indexOf(item.target_col) == -1) { // if we see a key first time - put it in keys
      keys.push(item.target_col)
    } else { // otherwise put it in duplicated keys
      keysDuplicates.push(item.target_col)
    }
  })
  if (keysDuplicates.length) {
    return keysDuplicates.map(key => arr.filter(item => item.target_col === key))
  }
  
  return arr
}

console.log(checkDuplicates(arr));

删除重复的元素

1 个答案: