Question

我需要有关向我已经运行的sql查询添加过滤器的帮助。我需要根据另一个表中的结果过滤结果。在不添加过滤器的情况下，代码可以正常工作，但是一旦添加，我会收到以下错误消息“警告：mysqli_num_rows（）期望参数1为mysqli_result，在第10行的C：\ xampp \ htdocs \ buff \ marketplace.php中给出布尔值”

这是我的查询代码：

$sql = "SELECT id, uid, jobId, serviceName, budget, description, start_date, end_date, date_created, priority, lat, lng, distance
                FROM (
                SELECT z.id,
                      z.uid,
                      z.jobId,
                      z.serviceName,
                      z.budget,
                      z.description,
                      z.start_date,
                      z.end_date,
                      z.date_created,
                      z.priority,
                      z.lat, z.lng,
                      p.radius,
                      p.distance_unit
                               * DEGREES(ACOS(COS(RADIANS(p.latpoint))
                               * COS(RADIANS(z.lat))
                               * COS(RADIANS(p.longpoint - z.lng))
                               + SIN(RADIANS(p.latpoint))
                               * SIN(RADIANS(z.lat)))) AS distance
                FROM marketplace AS z
                JOIN (   /* these are the query parameters */
                      SELECT  $lat  AS latpoint,  $lng AS longpoint,
                              50.0 AS radius,      111.045 AS distance_unit
                  ) AS p

                WHERE marketplace.sid IN (SELECT sid FROM selectedservice WHERE uid=$uid AND is_approve=1) AND status=1 AND uid != $uid AND z.lat
                   BETWEEN p.latpoint  - (p.radius / p.distance_unit)
                       AND p.latpoint  + (p.radius / p.distance_unit)
                  AND z.lng
                   BETWEEN p.longpoint - (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
                       AND p.longpoint + (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
                ) AS d
                WHERE distance <= radius
                ORDER BY distance
                LIMIT 15";

这是我添加的用于过滤结果的行：

marketplace.sid IN (SELECT sid FROM selectedservice WHERE uid=$uid AND is_approve=1)

这是当前没有过滤器的其余代码。

$sql = "SELECT id, uid, jobId, serviceName, budget, description, start_date, end_date, date_created, priority, lat, lng, distance
                FROM (
                SELECT z.id,
                      z.uid,
                      z.jobId,
                      z.serviceName,
                      z.budget,
                      z.description,
                      z.start_date,
                      z.end_date,
                      z.date_created,
                      z.priority,
                      z.lat, z.lng,
                      p.radius,
                      p.distance_unit
                               * DEGREES(ACOS(COS(RADIANS(p.latpoint))
                               * COS(RADIANS(z.lat))
                               * COS(RADIANS(p.longpoint - z.lng))
                               + SIN(RADIANS(p.latpoint))
                               * SIN(RADIANS(z.lat)))) AS distance
                FROM marketplace AS z
                JOIN (   /* these are the query parameters */
                      SELECT  $lat  AS latpoint,  $lng AS longpoint,
                              50.0 AS radius,      111.045 AS distance_unit
                  ) AS p

                WHERE status=1 AND uid != $uid AND z.lat
                   BETWEEN p.latpoint  - (p.radius / p.distance_unit)
                       AND p.latpoint  + (p.radius / p.distance_unit)
                  AND z.lng
                   BETWEEN p.longpoint - (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
                       AND p.longpoint + (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
                ) AS d
                WHERE distance <= radius
                ORDER BY distance
                LIMIT 15";

selectedservice和marketplace是具有sid和uid字段的表。 $ uid是整个页面中可用的登录用户ID。

我只需要知道如何挤压上面的过滤器以显示为用户启用的结果，而不是所有结果。任何帮助将不胜感激。

使用另一个表的结果过滤mysql查询结果

0 个答案: