Question

学习HTML和JavaScript，我试图根据通过表单提交的输入来为API请求形成自定义URL。我已经能够制作大多数URL，但是在将URL字符串连接到“？”之后却遇到了问题。提交动作时。我到目前为止仅凭文档和论坛帖子就做到了这一点，但无法弄清楚如何完成此操作，只想问一个人。

<div id="stock_quote_iex">
    <form id="get_stock_quote_form" onsubmit="get_stock_quote()" method="GET">
        <p>Enter Symbol and API Key</p>
        <input id="symbol" type="text" placeholder="Symbol">
        <input id="api_key" type="text" placeholder="API_KEY">
        <input type="submit" value="Submit">
    </form>
</div>

<script language="javascript" type="text/javascript">
    function get_stock_quote()
    {
        var form = document.getElementById('get_stock_quote_form')
        var symbol = document.getElementById('symbol').value
        var api_key = document.getElementById('api_key').value
        var action_src = "https://sandbox.iexapis.com/stable/stock/" + symbol + "/quote?token=" + api_key

        form.action = action_src;
    }
</script>

Example inputs:
symbol = NFLX
API_KEY = pk_s0m3rand0mphra5e

Expected output:
https://sandbox.iexapis.com/stable/stock/NFLX/quote?token=pk_s0m3rand0mphra5e

Actual output:
https://sandbox.iexapis.com/stable/stock/NFLX/quote?

Answer 1

已通过从字符串连接中删除查询参数并使用API_Key上的name属性来更正。

<div id="stock_quote_iex">
    <form id="get_stock_quote_form" onsubmit="get_stock_quote()" method="GET">
        <p>Enter Symbol and API Key</p>
        <input id="symbol" type="text" placeholder="Symbol">
        <input id="api_key" name="token" type="text" placeholder="API_KEY">
        <input type="submit" value="Submit">
    </form>
</div>

<script language="javascript" type="text/javascript">
    function get_stock_quote()
    {
        var form = document.getElementById('get_stock_quote_form')
        var symbol = document.getElementById('symbol').value
        var action_src = "https://sandbox.iexapis.com/stable/stock/" + symbol + "/quote"

        form.action = action_src;
    }
</script>

用自定义网址替换表单操作

1 个答案: