仅根据百分比参数返回值的函数

Question

给定一个百分比0-100，一个人怎么可能在x％的时间内返回值“ y”。

例如，如果我要在30％的时间内返回字符串“是”

myfunc(30)

def myfunc(percentage):
   # Do something here that "yes" will return 30% of the time
   return "yes"

Answer 1

使用function calcTime(city, offset) { // create Date object for current location var d = new Date(); // convert to msec // add local time zone offset // get UTC time in msec var utc = d.getTime() + (d.getTimezoneOffset() * 60000); // create new Date object for different city // using supplied offset var nd = new Date(utc + (3600000*offset)); // return time as a string return "The local time in " + city + " is " + nd.toLocaleString(); }

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