我的目标是每小时执行一次简单的任务。在应用程序启动时,我用ExistingPeriodicWorkPolicy.KEEP
标志注册了唯一的定期工作。
这是我的实现方式
public class MyWorker extends Worker {
public MyWorker(Context context, WorkerParameters workerParams) {
super(context, workerParams);
// I don't do anyting with workerParams
}
public static void enqueueWork() {
Constraints constraints = new Constraints.Builder()
.setRequiresBatteryNotLow(true)
.build();
PeriodicWorkRequest request = new PeriodicWorkRequest
.Builder(MyWorker.class, 1, TimeUnit.HOURS)
.setConstraints(constraints)
.addTag("MyWorkerWork")
.build();
WorkManager.getInstance().enqueueUniquePeriodicWork("MyWorkerWork",
ExistingPeriodicWorkPolicy.KEEP, request);
}
@NonNull
@Override
public Result doWork() {
Log.i(TAG, "doWork");
return Result.success();
}
}
我唯一叫enqueueWork()
的地方是Application#onCreate
。
public class MyApplication extends Application {
@Override
public void onCreate() {
super.onCreate();
MyWorker.enqueueWork();
}
}
以上安装程序运行正常。问题之一是有时doWork
连续两次被调用,之间间隔约30秒。这不是100%可重现的,但是当我整夜离开手机并于第二天回来并首次打开手机显示屏时,我经常会看到这种情况。
典型日志如下:
01-13 13:29:04.601 19018 19449 I/MyApp: doWork
01-13 13:29:04.700 19018 19124 I/WM-WorkerWrapper: Worker result SUCCESS for Work [ id=37064d6c-297b-4c0d-9fd7-xxxxxxxxxxxx, tags={ com.xxx.MyWorker, MyWorkerWork } ]
01-13 13:29:42.203 19018 19482 I/MyApp: doWork
01-13 13:29:42.292 19018 19145 I/WM-WorkerWrapper: Worker result SUCCESS for Work [ id=37064d6c-297b-4c0d-9fd7-xxxxxxxxxxxx, tags={ com.xxx.MyWorker, MyWorkerWork } ]
有趣的是,这种情况不会被进程杀死。如果您以前曾经历过,请提供帮助。