通过云功能通过云功能发送邮件

时间:2020-01-13 21:20:50

标签: python google-cloud-platform google-cloud-functions google-cloud-storage sendmail

我试图配置云功能,以便在不使用第三方工具的情况下,只要文件被推送到GCP中的一个云存储桶中,就可以发送邮件。我已经在这里检查了概念,并确保我的发件人电子邮件已注册为授权发件人。

https://cloud.google.com/appengine/docs/standard/python/mail/sending-mail-with-mail-api

requirements.txt添加了以下值:

google-cloud-storage==1.23.0
googleapis-common-protos==1.3.5
google-api-python-client
需求文件中的

。但是仍然出现相同的错误。

但是,当我尝试使用以下脚本时,最终出现此错误:

ModuleNotFoundError: No module named 'google.appengine' .

提前了解您的建议和帮助。


from google.appengine.api import app_identity
from google.appengine.api import mail
import webapp2


def send_approved_mail(sender_address):
    # [START send_mail]
    mail.send_mail(sender=sender_address,
                   to="Albert Johnson <Albert.Johnson@example.com>",
                   subject="Your account has been approved",
                   body="""Dear Albert:
Your example.com account has been approved.  You can now visit
http://www.example.com/ and sign in using your Google Account to
access new features.
Please let us know if you have any questions.
The example.com Team
""")
    # [END send_mail]


class SendMailHandler(webapp2.RequestHandler):
    def get(self):
        send_approved_mail('{}@appspot.gserviceaccount.com'.format(
            app_identity.get_application_id()))
        self.response.content_type = 'text/plain'
        self.response.write('Sent an email to Albert.')


app = webapp2.WSGIApplication([
    ('/send_mail', SendMailHandler),
], debug=True)

1 个答案:

答案 0 :(得分:1)

您需要与第三方电子邮件服务(例如Sendgrid)集成,并将您的Cloud Function构建为Cloud Function,例如:

# using SendGrid's Python Library
# https://github.com/sendgrid/sendgrid-python
import os
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import Mail

sg = SendGridAPIClient(os.environ.get('SENDGRID_API_KEY'))

def send_mail(data, context):
    message = Mail(
        from_email='from_email@example.com',
        to_emails='to@example.com',
        subject='This is the subject',
        html_content='This is the content'
    )
    response = sg.send(message)

有关更多详细信息,请参见https://cloud.google.com/functions/docs/tutorials/sendgrid