Question

我有两个数组

 {
"products": [
    {
        "name": "Jivi",
        "Hint": "45-60 IE/kg alle 5 Tage\n60 IE 1x/Woche\n30-40 IE 2 x/Woche",
        "frequency": ["1", "2", "8"]
    },
    {
        "name": "Adynovi",
        "Hint": "40-50 IE/kg 2x/Woche im Abstand von 3-4 Tagen",
        "frequency": ["2", "6", "7"]
    },
    {
        "name": "Esperoct",
        "Hint": "\"50 IE/kg \nalle 4 Tage\"\n",
        "frequency": ["7"]
    }
],
"haufigkeit" : [
    {
        "name": "1x / Woche",
        "id": 1,
        "value": 52.1428571429
    },
    {
        "name": "2x / Woche",
        "value": 104.2857142857143,
        "id": 2
    }
]
}

我有一个使用Vuejs的选择下拉列表，其中products.name正在呈现。

 <select v-model="selectFrequency">
        <option v-for="(level1,index) in dataJson.products"
                v-bind:value="level1.frequency">{{level1.name}}</option>
      </select>

例如，当我选择Jivi时，我想将frequency的{{1}}中的数字与products中的id中的数字进行比较，，然后显示haufigkeit中的name

这就是我正在尝试的

haufigkeit

我已经尝试了两天，但它给我一个错误computed:{ selectFrequency:function(){ let results= this.haufigkeit.filter(array=>array.every(item => this.products.filter(group=>group.frequency.includes(item)))); } }。有人可以建议我在哪里做错了吗？

Answer 1

编辑：好的，现在我了解了，类似这样的方法应该对您有用：https://jsfiddle.net/q9grc04s/

如果选择一个产品，您将看到该产品显示在所选频率中包含ID的所有haufigkeit。

<template>
<div>
  <div>
    <select v-model="selectedFrequency">
      <option
        v-for="(level1, i) in products"
        :key="i"
        :value="level1.frequency"
      >
        {{level1.name}}
      </option>
    </select>
  </div>
  <div>
    <h1>Haufigkeit Matches:</h1>
    <ul v-if="haufigkeitMatches">
      <li v-for="match in haufigkeitMatches">{{ match.name }}</li>
    </ul>
  </div>
</div>
</template>

<script>
export default {
  data: {
    selectedFrequency: [],
    products: [
        {
            name: "Jivi",
            Hint: "45-60 IE/kg alle 5 Tage\n60 IE 1x/Woche\n30-40 IE 2 x/Woche",
            frequency: [1, 2, 8]
        },
        {
            name: "Adynovi",
            Hint: "40-50 IE/kg 2x/Woche im Abstand von 3-4 Tagen",
            frequency: [2, 6, 7]
        },
        {
            name: "Esperoct",
            Hint: "\"50 IE/kg \nalle 4 Tage\"\n",
            frequency: [7]
        }
    ],
    haufigkeit : [
        {
            name: "1x / Woche",
            id: 1,
            value: 52.1428571429
        },
        {
            name: "2x / Woche",
            value: 104.2857142857143,
            id: 2
        }
    ]
  },
  computed: {
    haufigkeitMatches(){
        return this.haufigkeit.filter(x => this.selectedFrequency.includes(x.id))
    }
  }
}
</script>

注意：抱歉，所有编辑我都想掌握stackoverflow编辑器，但是JS小提琴链接是一个有效的解决方案。

Answer 2

您可以使用Javascript some功能。在下面的示例中，我将返回haufigkeit数组的ID，该ID等于产品的频率

var data = {
    "products": [
        {
            "name": "Jivi",
            "Hint": "45-60 IE/kg alle 5 Tage\n60 IE 1x/Woche\n30-40 IE 2 x/Woche",
            "frequency": ["1", "2", "8"]
        },
        {
            "name": "Adynovi",
            "Hint": "40-50 IE/kg 2x/Woche im Abstand von 3-4 Tagen",
            "frequency": ["2", "6", "7"]
        },
        {
            "name": "Esperoct",
            "Hint": "\"50 IE/kg \nalle 4 Tage\"\n",
            "frequency": ["7"]
        }
    ],
    "haufigkeit" : [
        {
            "name": "1x / Woche",
            "id": 1,
            "value": 52.1428571429
        },
        {
            "name": "2x / Woche",
            "value": 104.2857142857143,
            "id": 2
        }
    ]
};

var result = [];
function selectFrequency(){

    data.products.forEach(elem => {
      
        elem.frequency.forEach(fre =>{
            var arr = data.haufigkeit;
            if(arr.some(arr => arr.id == fre))
                result.push(fre);
        })
    });
    return result;
}

console.log(selectFrequency());

根据另一个数组Vuejs过滤数组

2 个答案: