我遇到了gd库问题。当我使用以下代码时
<script type="text/javascript">
$.fn.infiniteCarousel = function () {
function repeat(str, num) {
return new Array( num + 1 ).join( str );
}
return this.each(function () {
var $wrapper = $('> div', this).css('overflow', 'hidden'),
$slider = $wrapper.find('> ul'),
$items = $slider.find('> li'),
$single = $items.filter(':first'),
singleWidth = $single.outerWidth(),
visible = Math.ceil($wrapper.innerWidth() / singleWidth), // note: doesn't include padding or border
currentPage = 1,
pages = Math.ceil($items.length / visible);
// 1. Pad so that 'visible' number will always be seen, otherwise create empty items
if (($items.length % visible) != 0) {
$slider.append(repeat('<li class="empty" />', visible - ($items.length % visible)));
$items = $slider.find('> li');
}
// 2. Top and tail the list with 'visible' number of items, top has the last section, and tail has the first
$items.filter(':first').before($items.slice(- visible).clone().addClass('cloned'));
$items.filter(':last').after($items.slice(0, visible).clone().addClass('cloned'));
$items = $slider.find('> li'); // reselect
// 3. Set the left position to the first 'real' item
$wrapper.scrollLeft(singleWidth * visible);
// 4. paging function
function gotoPage(page) {
var dir = page < currentPage ? -1 : 1,
n = Math.abs(currentPage - page),
left = singleWidth * dir * visible * n;
$wrapper.filter(':not(:animated)').animate({
scrollLeft : '+=' + left
}, 500, function () {
if (page == 0) {
$wrapper.scrollLeft(singleWidth * visible * pages);
page = pages;
} else if (page > pages) {
$wrapper.scrollLeft(singleWidth * visible);
// reset back to start position
page = 1;
}
currentPage = page;
});
return false;
}
$wrapper.after('<a class="arrow back"><</a><a class="arrow forward">></a>');
// 5. Bind to the forward and back buttons
$('a.back', this).click(function () {
return gotoPage(currentPage - 1);
});
$('a.forward', this).click(function () {
return gotoPage(currentPage + 1);
});
// create a public interface to move to a specific page
$(this).bind('goto', function (event, page) {
gotoPage(page);
});
});
};
$(document).ready(function () {
$('.infiniteCarousel').infiniteCarousel();
$("a.pictureThumb").fancybox({
'autoScale' : true,
'autoDimension' : true,
'transitionIn' : 'elastic',
'transitionOut' : 'elastic',
'speedIn' : 300,
'speedOut' : 200,
'hideOnOverlayClick' : true,
'hideOnContentClick': false
});
});
</script>
将此作为图像生成器,唯一出现的就是编程代码而不是图像。这个脚本使用了不同的滚动条,但是由于我放了这个新的滚动脚本(如上所示),我遇到了生成图像的问题(IE只显示了加载图标),FireFox实际上显示了编程代码。
以下是调用GD函数的代码:
<div class="infiniteCarousel">
<div class="wrapper">
<ul>
<?php
do { ?>
<li><a class="pictureThumb" href="picture.php?imgID=<?php $pieces = explode('_', $row_rsPictures['PictureFile']); echo $pieces[0]."_".$pieces[1]."_".$pieces[2]; if ($pieces[3] == "NN"){ echo "_NN_".$pieces[4]."_".$pieces[5];; } else { echo "_".$pieces[3]."_".$pieces[4]; } ?>&thumb=Y" title="<a href='addToCart.php?T=Pic?ID=<?php echo $row_rsPictures['PictureID']; ?>' target='_parent' style='color:#fe6d00' >Add This Image To Your Shopping Cart</a><br><?php echo $row_rsPictures['BoatName'];if($row_rsPictures['BoatNumber'] != "") {
echo " #".$row_rsPictures['BoatNumber'];
} ?><br>driven by: <?php echo $row_rsPictures['DriverName']; ?> at the <?php
$AssocName_array = explode('_', $row_rsPictures['Acronym']);
$AssocName = $AssocName_array[0];
if ($AssocName == "Various") {
$AssocName = "";
}
if ($row_rsPictures['DateTo'] != ""){
$EventYear = date("Y", strtotime($row_rsPictures['DateTo']));
}
else { $EventYear = "";
}
echo $EventYear." ".$AssocName." ".$row_rsPictures['EventName'];?><br>Picture Viewed (<?php echo $row_rsPictures['Views']; ?>) since posted on <?php echo date("n-j-Y", strtotime($row_rsPictures['DatePosted'])); ?>" rel="group">
<img src="../images/gallery/<?php $raceYear = explode('_', $row_rsPictures['EventOverlay']); echo $raceYear[0]; ?>/<?php echo $row_rsPictures['EventOverlay']; ?>/thumb/<?php echo $row_rsPictures['PictureFile']; ?>.jpg" alt="FileName: <?php echo $row_rsPictures['PictureFile'];?>"></a></li>
<?php
} while ($row_rsPictures = mysql_fetch_assoc($rsPictures));
mysql_data_seek($rsPictures, 0);
?>
</ul>
</div>
</div>
和生成图像的单独php文件。
<?php
$filename = explode("_", $_GET['imgID']);
$folder = $filename[0];
$subFolder = $filename[0]."_".$filename[1]."_".$filename[2];
if($filename[3] == "NN") {
$subFolder = $subFolder."_NN";
}
$shot = "../images/gallery/".$folder."/".$subFolder."/".$_GET['imgID'].".jpg";
$watermark = "../images/gallery/watermark.png";
header("Content-type: image/jpg");
$photoImage = ImageCreateFromJPEG($shot);
ImageAlphaBlending($photoImage, true);
$logoImage2 = ImageCreateFromPNG($watermark);
$im = imagecreatetruecolor(800, 16);
$im2 = imagecreatetruecolor(800, 10);
$white = imagecolorallocate($im, 255, 255, 255);
//imagefilledrectangle($photoImage, 0, 0, 796, 15, $white);
$grey = imagecolorallocate($im2, 128, 128, 128);
$red = imagecolorallocate($im2, 255, 0, 0);
//$im = imagecreatetruecolor(796, 25);
$text = $_GET['imgID'];
$text2 = 'COPYRIGHT 1997 - 2011 - DRAGBOATS.COM - ALL RIGHTS RESERVED';
$text3 = '^ THIS BAR WILL NOT APPEAR ON PURCHASED PRINTS ^';
//$black = imagecolorallocate($photoImage, 0, 0, 0);
imagestring($im, 2, 10, 1, $text, $white);
imagestring($im, 2, 440, 1, $text2, $white);
imagestring($im2, 1, 290, 1, $text3, $white);
ImageCopy($photoImage, $im, 0, 0, 0, 0, 800, 16);
ImageCopy($photoImage, $im2, 0, 17, 0, 0, 800, 10);
ImageCopy($photoImage, $logoImage2, 0, 0, 0, 0, 800, 525);
ImageJPEG($photoImage); // output to browser
ImageDestroy($photoImage);
ImageDestroy($logoImage2);
?>
某处存在导致问题的冲突,我无法找到它。
感谢任何帮助。
可以在http://randykrohn.com/gallery/pictures_test.php?BoatID=881
找到实际页面答案 0 :(得分:0)
您似乎将原始图像数据(.jpg中的字节)文件输出到图库弹出窗口,其中包含一个不合适的标题,以便将imgae解释为文本而不是图像。
如果“......对GD功能的调用”下的最后一段代码都在一个文件中,那就可以解释原因。您正在输出一大块html,然后是原始图像数据,然后将其插入到图库弹出窗口中。您已经输出了一些html,Content-type
标题无法生效。如果您检查错误日志(和/或实际启用错误/警告),您无疑会看到PHP中通常的“无法修改标题,从XXX行开始输出”警告。
答案 1 :(得分:0)
尝试在php.ini
文件中将php内存限制设置为96M(128M - 推荐)。如果您无权访问该文件,只需将ini_set('memory_limit', '128M');
添加到您的php文件即可。它必须有助于解决这个问题。
答案 2 :(得分:0)
没有帮助,但我自己想出来了。需要告诉FancyBox明确地打开链接作为图像(即:fancybox({'type':'image'});现在好了!谢谢你们帮助你们!