Question

我有一个对象：

const ratingSettings = {performer: true, chiefEngineer: true, engineer: true, customer: true}

我想将其转换为类似GraphQL的字符串，就像用反斜杠将所有双引号转义一样：

"{\"performer\":true,\"chiefEngineer\":true,\"engineer\":true,\"customer\":true}"

我尝试了以下操作：

const ratingSettings = JSON.stringify({performer: true, chiefEngineer: true, engineer: true, customer: true})

const getMutationObject = data => Object.keys(data).map(key => `${key}: "${data[key]}"`).join(' ')

const userData = getMutationObject(ratingSettings);

但是我没有得到我所需要的：

"{"performer":true,"chiefEngineer":true,"engineer":true,"customer":true}"

我需要所有双引号都用\

转义

提前感谢提供的解决方案！

Answer 1

JSON.stringify对象，然后使用.replace将所有"替换为\\"：

const ratingSettings = {performer: true, chiefEngineer: true, engineer: true, customer: true}
const escapedJSON = JSON.stringify(ratingSettings)
  .replace(/"/g, '\\"');
console.log(escapedJSON);

Answer 2

但是我没有得到我所需要的：
"{"performer":true,"chiefEngineer":true,"engineer":true,"customer":true}"

那不是你所拥有的。它是GUI中的一种表示形式，它显示您有一个包含"的字符串（因此在外部带有{"performer":true,"chiefEngineer":true,"engineer":true,"customer":true}）。外部引号根本不是值的一部分。

要在转义其中所有"的同时用"包裹已经拥有的字符串：使用JSON.stringify 再次：

const ratingSettings = JSON.stringify(JSON.stringify({performer: true, chiefEngineer: true, engineer: true, customer: true}))

Answer 3

const string = JSON.stringify(object);
const escaped = string.replace(/"/g, '\"');

Answer 4

JSON.stringify应该为您产生所需的结果。

    const expectedResult = "{\"performer\":true,\"chiefEngineer\":true,\"engineer\":true,\"customer\":true}";
    const result = JSON.stringify({performer: true, chiefEngineer: true, engineer: true, customer: true});
    
    if(result === expectedResult) {
    	console.log('You are doing it right!!!');
    }

当您记录转义字符串的结果时，您不会在控制台中看到转义字符。

用反斜杠转义双引号

4 个答案: